將元素添加到數組中的Swift語法錯誤

Question

其中存在語法錯誤。新斯威夫特:(

var inputString: String = "Hello its question? </question> Oky its the answer" 

let splitter: String = "</question>" 
var splittedArray = [inputString .componentsSeparatedByString(splitter)] 


var questionIndex = 0 
var answerIndex = 0 
var mQuestions = [] 
var mAnswers = [] 


for var index = 0; index < splittedArray.count; ++index { 
if index % 2 == 0{ 
    // Question comes first 
    splittedArray.append(mQuestions[questionIndex]) 
    questionIndex++ 
}else{ 
    // Answer comes second 

splittedArray.append(mAnswers[answerIndex]) 
    answerIndex++ 
    } 
} 

錯誤是：

對象並不可轉換爲字符串，

在這行代碼

splittedArray.append(mQuestions[questionIndex]) 

Answer 1

確有語法錯誤，但是這還不是全部：

• 可以作爲你與[inputString.components...]
• 做不在線Objective-C代碼你不能沒有指定初始化一個空數組其類型
• 你有對象和參數在appends

---

逆轉

這裏是一個快速重寫尋址上述：

import Foundation 

var inputString = "Hello its question? </question> Oky its the answer" 

let splitter = "</question>" 
var splittedArray = inputString.componentsSeparatedByString(splitter) as [String] 

var mQuestions = [String]() 
var mAnswers = [String]() 

while splittedArray.count >= 2 { 
    mQuestions.append(splittedArray.removeAtIndex(0)) 
    mAnswers.append(splittedArray.removeAtIndex(0)) 
} 

Answer 2

var splittedArray = [inputString .componentsSeparatedByString(splitter)] 

。

一個objective-c hango的位ver在這裏。有了這些方括號，你就可以將這個數組放在裏面。這將使splittedArray有錯誤的類型和錯誤的內容。

一旦這個程序編譯它也會崩潰，因爲你使用一個出界索引從空的mQuestions數組中追加到splittedArray。