jQuery對象是否被填充

Question

我想檢查jQuery對象是否包含值。

var objContactList = new Object(); 
objContacList.Address = "xyz abc"; 
objContactList.Email = "abc@abc.com"; 
objContactList.MobileNo = "9013027233"; 

現在，我要檢查，如果ObjContactList.Address和objContactList.MobileNo充滿與否。爲此，我這樣做：

$.each(objContactList, function(i, val) { 
    if (objContactList[i].val() == '') { 
     // do this 
    } 
}) 

Answer 1

試試這個，它的工作

var objContactList = new Object(); 
 
    objContactList.Address = "xyz abc"; 
 
    objContactList.Email = "abc@abc.com"; 
 
    objContactList.MobileNo = "9013027233"; 
 
    objContactList.pin = ""; 
 
    
 

 
for(var propertyName in objContactList) { 
 
    if(objContactList.hasOwnProperty(propertyName)){ 
 
    var value = objContactList[propertyName] 
 
    if(value == ""){ 
 
    console.log(propertyName + " has no value"); 
 
    } 
 
    else{ 
 
    console.log(propertyName + " has value"); 
 
    } 
 
     } 
 
    
 
    
 
}

Answer 2

嗨，你正在使用對象，以便利用每一個你無法重複這樣更好ü可以檢查使用創建兩種方式

1路

var objContactList = new Object(); 
objContactList.Address = "xyz abc"; 
objContactList.Email = "abc@abc.com"; 
objContactList.MobileNo = "9013027233"; 

if(objContactList.hasOwnProperty("Address ")){ 
    alert("Address is there"); 
} 
if(objContactList.hasOwnProperty("Email")){ 
    alert("email is there"); 
} 

2WAY

var objContactList = new Object(); 
    objContactList.Address = "xyz abc"; 
    objContactList.Email = "abc@abc.com"; 
    objContactList.MobileNo = "9013027233"; 

    if(objContactList.Address != "" || objContactList.Address != undefined){ 
     alert("Address is there"); 
    } 

如果u有多個對象，然後推到陣列

JS

var myarray = []; 

var objContactList = new Object(); 
objContactList.Address = "xyz abc"; 
objContactList.Email = "abc@abc.com"; 
objContactList.MobileNo = "9013027233"; 

myarray.push(objContactList); 
var objContactList2 = new Object(); 
objContactList2.Address = "xyz abc"; 
objContactList2.Email = "abc@abc.com"; 
objContactList2.MobileNo = "9013027233"; 

myarray.push(objContactList2); 

for (var i = 0; i < myarray.length; i++) { 
    if (myarray[i].Address != "") { 
     alert("Address is there"); 
    } 
} 

1的檢查方法的對象是存在2方法來檢查存在價值

Answer 3

試試這個：

var objContactList = new Object(); 
     objContactList.Address = "xyz abc"; 
     objContactList.Email = "abc@abc.com"; 
     objContactList.MobileNo = "9013027233"; 

     if (objContactList.hasOwnProperty('Address')) { 
      if (objContactList.Address != "") { 
       alert('Address is : ' + objContactList.Address); 
      } else { 
       alert(' Address is empty'); 
      } 
     } 
     if (objContactList.hasOwnProperty('Email')) { 
      if (objContactList.Email != "") { 
       alert('Email is : ' + objContactList.Email); 
      } else { 
       alert(' Email is empty'); 
      } 
     } 
     if (objContactList.hasOwnProperty('MobileNo')) { 
      if (objContactList.MobileNo != "") { 
       alert('MobileNo is : ' + objContactList.MobileNo); 
      } else { 
       alert(' MobileNo is empty'); 
      } 
     } 

https://jsfiddle.net/8apatfy6/