通過嵌套陣列控制器與查看laravel

Question

我是新來laravel，我試圖從明確的問題 here

我控制器類似如下：

foreach($users as $user){ 
    $message[] = Model::where('id',$user->id)->get(); 
} 
$data['tests'] = $message; 
return View::make('user.index', $data); 

我的看法是：

@foreach($tests['message'] as $test) 
    id : {{$test->id}} 
@endforeach 

這給了我Undefined index: message

我已經在控制器中轉儲了$data。我的數組如下所示。在return語句之前，我將var_dump放置在控制器中。我的var_dump($data)顯示：

array(1) { 
     ["tests"] => array(2) { 
      [0] => object(Illuminate\ Database\ Eloquent\ Collection) #515 (1) { ["items":protected]= > array(2) { 
       [0] => ["attributes": protected] => array(14) { 
        ["id"] => string(3) "12".... 

     } 
    } 
      [1] => object(Illuminate\ Database\ Eloquent\ Collection) #515 (1) { ["items":protected]= > array(2) { 
       [0] => ["attributes": protected] => array(14) { 
        ["id"] => string(3) "12".... 

     } 
    } 
    } 

我做錯了什麼。請幫助我

Answer 1

@foreach($tests as $test) 
//$test is an array returned by get query. 
    @foreach($test as $item) 
    id : {{$item->id}} 
    @endforeach 
@endforeach 

獲取返回數組，如果你想返回一個元素，使用查找（）或第（）。

Answer 2

您的$tests['message']應該是$tests，因爲您尚未在控制器中定義消息。

$message = array(); 
foreach($users as $user){ 
    $message[] = Model::where('id',$user->id)->get(); 
} 
$data['tests'] = $message; 
return View::make('user.index', $data); 

查看

@foreach($tests as $test) 
    id : {{$test->id}} 
@endforeach 

Answer 3

試試這個：

$users = App\User::all() 
foreach($users as $user){ 
    $message[] = Model::where('id',$user->id)->get(); 
} 
$data['tests'] = $message; 
return view('user.index', compact('data')); 

在視圖/ user.index.blade.php

@foreach($data['tests'] as $test) 
    id : {{$test->id}} 
@endforeach