2011-04-12 49 views
2

我有一個hibernate實體(paygrade)與多個孩子(paysteps),我試圖在應用程序中查詢這些孩子。不幸的是,我只能檢索查詢的第一條記錄。這裏有休眠一對多不返回完整的結果集

public class Paygrade extends Persistent { 

    @Id 
    @Column(length = 80, updatable=false) 
    private String code; 

    @Column(length = 80, updatable=false) 
    private String name; 

    @OneToMany(mappedBy = "paygrade", fetch = FetchType.LAZY) 
    @ForeignKey(name = "none") 
    private Set<Paystep> paygradeSteps = new HashSet<Paystep>(); 

    // getters and setters 
} 


@IdClass(PaystepPK.class) 
public class Paystep { 

    @Id 
    @Column(length = 80, updatable=false) 
    protected String gradeCode; 

    @Column(length = 80, updatable=false) 
    protected String gradeName; 

    @Id 
    @Column(length = 80, updatable=false) 
    protected String scaleCode; 

    @Column(length = 80, updatable=false) 
    protected String scaleName; 

    @Column(length = 80, updatable=false) 
    protected String scalePoint; 

    @Column(updatable=false) 
    protected Long scaleValue; 

    @ManyToOne 
    @ForeignKey(name = "none") 
    @JoinColumn (name="grade_code", updatable = false, insertable = false) 
    private Paygrade paygrade; 

    // getters and setters 

} 

下面的查詢是Hibernate調用getPaygradeSteps當paygrade實例()方法調用的實體:

Hibernate: 
/* load one-to-many ...Paygrade.paygradeSteps */ select 
    paygradest0_.grade_code as grade1_38_1_, 
    paygradest0_.grade_code as grade1_1_, 
    paygradest0_.scale_code as scale2_1_, 
    paygradest0_.grade_code as grade1_39_0_, 
    paygradest0_.scale_code as scale2_39_0_, 
    paygradest0_.grade_name as grade3_39_0_, 
    paygradest0_.scale_name as scale4_39_0_, 
    paygradest0_.scale_point as scale5_39_0_, 
    paygradest0_.scale_value as scale6_39_0_ 
from 
    tv_grade_point paygradest0_ 
where 
    paygradest0_.grade_code= 'Grade 9' 

查詢從數據庫返回9個結果,但冬眠只有永遠檢索第一條記錄。我假設它可能與paystep的組合鍵(使用休眠與遺留數據庫相關的危險)有關。

有誰知道爲什麼會出現這種行爲?

回答

0

您需要在OneToMany引用中指定連接列"grade_code"並使其反轉。

順便說一句:您的問題中的SQL查詢正在檢索tv_grade_point,而不是Paystep。