行,所以我有這個PHP腳本:的preg_replace不工作:(
<?php
$stringz = "Dan likes to eat pears and his favorite color is green!";
$patterns = array("/pears/","/green/");
$string = preg_replace($patterns, '<b>\\1</b>', $stringz);
echo "<textarea rows='30' cols='100'>$string</textarea>";
?>
,當我運行它,我得到這個: Dan likes to eat <b></b> and his favorite color is <b></b>!
的是假設有一個字。 ..但它不...
其實你總是在'\ 0`中捕捉整個事物,不管你是否有括號組。 – cambraca 2010-11-23 01:26:02
對,我的意思是他沒有*明確地捕捉任何東西。 :) – Alex 2010-11-23 01:27:07