使用Open XML SDK修復Word中的單元格寬度

Question

我在docx文件中有一行表，我想添加一些行。對於第一個存在的行，我將GridSpan設置爲3.在下一個行中，我只需要添加一行與兩個單元格，然後獲得圖片上的結果。我怎樣才能修復新的行寬到表寬度？當我在新行中只添加一個單元格時，我也想做同樣的事情。

我的代碼：

private static TableRow AddRow(WordprocessingDocument docx, Table tbl, int cellsQuantity) 
     { 
      TableRow newRow = new TableRow(); 

      var firstCell = tbl.Descendants<TableRow>().First() 
        .Descendants<TableCell>().First(); 

      firstCell.Append(new TableCellProperties(new GridSpan() { Val = 3 })); 

      for (int i = 0, max = cellsQuantity; i < max; i++) 
      { 
       // TableCellProperties tcp = new TableCellProperties(new TableCellWidth() { Width = firstCell.TableCellProperties.TableCellWidth.Width, Type = firstCell.TableCellProperties.TableCellWidth.Type }); 
       TableCell cell = new TableCell(new Paragraph(new Run(new Text("test")))); 
       newRow.AppendChild(cell); 
      } 

      tbl.Append(newRow); 

      return newRow; 
     } 

Answer 1

好了，我的事情我知道了:)

private static TableRow AddRow(WordprocessingDocument docx, Table tbl, int cellsQuantity) 
     { 
      TableRow newRow = new TableRow(); 

      var grid = tbl.Descendants<TableGrid>().First(); 

      var firstCell = tbl.Descendants<TableRow>().First() 
        .Descendants<TableCell>().First(); 

      firstCell.Append(new TableCellProperties(new GridSpan() { Val = 4 })); 

      int ind = 0; 
      int[] widthPerColumn = new int[] { 3070, 1536, 1535, 3071 }; 
      grid.Descendants<GridColumn>().ToList().ForEach(x => 
      { 
       x.Width = widthPerColumn[ind++].ToString(); 
      }); 

      int[] gridSpan = null; 
      switch (cellsQuantity) 
      { 
       case 4: 
        gridSpan = new int[] { 1, 1, 1, 1 }; 
        break; 
       case 3: 
        gridSpan = new int[] { 1, 2, 1 }; 
        break; 
       case 2: 
        gridSpan = new int[] { 2, 2 }; 
        break; 
       case 1: 
        gridSpan = new int[] { 4 }; 
        break; 
       default: 
        throw new InvalidOperationException("The cellsQuantity variable must have a value from [1,4] range"); 
      } 

      for (int i = 0, max = cellsQuantity; i < max; i++) 
      { 
       TableCellProperties tcp = new TableCellProperties(new GridSpan() { Val = gridSpan[i] }); 
       TableCell cell = new TableCell(tcp, new Paragraph(new Run(new Text("test")))); 
       newRow.AppendChild(cell); 
      } 

      tbl.Append(newRow); 

      return newRow; 
     } 

Answer 2

TableCell tCell = new TableCell(); 

tCell.Append(new TableCellProperties(
    new GridSpan { Val = table.LastChild.ChildElements.Count }, 
    new Justification { Val = JustificationValues.Right }) 
);