我有這個示例代碼將提取每個標記的值。 而除此之外獲取標籤的類名..DOMDocument XPath查詢獲取類名稱和標記值
<?php
$doc = new DOMDocument;
$doc->loadxml(<<< eox
<tr class="calendar_row" data-eventid="42023">
<td class="date"/>
<td class="time">All Day</td>
<td class="currency">CAD</td>
<td class="impact">
<span title="Non-Economic" class="holiday"/>
</td>
<td class="event">
<span>Bank Holiday</span>
</td>
<td class="detail">
<a class="calendar_detail level1" data-level="1" title="Open Detail"/>
</td>
<td class="actual"/>
<td class="forecast"/>
<td class="previous"/>
<td class="graph"/>
</tr>
eox
);
$xpath = new DOMXPath($doc);
foreach($xpath->query('//tr[@data-eventid="42023"]/td[@class]') as $n) {
echo $n->nodeName.'-'.$n->nodeValue."<br />";
}
?>
使用上面的代碼片段,我要的是讓這些值即使一些標籤的arent良好的格式化(IM報廢Web源)..我如何在DOMDocument XPath查詢中執行此操作。我有麻煩「導致被讀取值是:
td-
td-All Day
td-CAD
td-
td-Bank Holiday
td-
td-
td-
td-
td-
代替:
date-
time-All Day
currency-CAD
impact-
event-Bank Holiday
detail-
actual-
forecast-
previous-
graph-