2012-07-03 68 views
8

我想將GestureDetector添加到活動的所有視圖(視圖組),而無需手動將其分配給每個視圖。此時onFling()僅在輕掃背景時激活,但在輕掃時則不激活。 BUTTON1。將GestureDetector設置爲所有子視圖

package com.app.example; 

import android.app.Activity; 
import android.content.Context; 
import android.graphics.Color; 
import android.os.Bundle; 
import android.util.Log; 
import android.view.GestureDetector; 
import android.view.MotionEvent; 
import android.view.GestureDetector.SimpleOnGestureListener; 
import android.view.View; 
import android.view.View.OnTouchListener; 
import android.widget.Button; 
import android.widget.LinearLayout; 

public class ExampleActivity extends Activity { 
    Context mContext = null; 

    @Override 
    public void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     mContext = this; 

     LinearLayout parent = new LinearLayout(mContext); 
     parent.setOrientation(LinearLayout.VERTICAL); 
     parent.setBackgroundColor(Color.RED); 

     Button button1 = new Button(mContext); 
     button1.setText("Button 1"); 
     Button button2 = new Button(mContext); 
     button2.setText("Button 2"); 

     parent.addView(button1); 
     parent.addView(button2); 

     final GestureDetector gestureDetector = new GestureDetector(
       new MyGestureDetector()); 

     parent.setOnTouchListener(new OnTouchListener() { 
      @Override 
      public boolean onTouch(View v, MotionEvent event) { 
       gestureDetector.onTouchEvent(event); 

       return true; 
      } 
     }); 

     setContentView(parent); 
    } 
} 

class MyGestureDetector extends SimpleOnGestureListener { 

    @Override 
    public boolean onFling(MotionEvent e1, MotionEvent e2, 
      float velocityX, float velocityY) { 

     // right to left 
     if(e1.getX() - e2.getX() > 10 && Math.abs(velocityX) > 20) { 
      Log.i("onFling", "right to left"); 

      return false; 

     // left to right 
     } else if (e2.getX() - e1.getX() > 10 && Math.abs(velocityX) > 20) { 
      Log.i("onFling", "left to right"); 

      return false; 
     } 

     return false; 
    } 

} 

回答