檢查上一個節點值的值並將當前值增加一個

如果與先前的房間無餘量值相等，我需要檢查特定酒店中每個可用房間的shrui值。其他值只有1。我曾嘗試過，它沒有奏效。以下是我的代碼。任何人都可以幫助我解決這個問題。檢查上一個節點值的值並將當前值增加一個

<xsl:for-each select="hm:AvailableRoom "> 
      <availableroom>   
       <hotelcode> 
        <xsl:value-of select="preceding-sibling::hm:HotelInfo/hm:Code"/> 
       </hotelcode>    
       <xsl:for-each select="hm:HotelOccupancy "> 
       <roomcount> 
        <xsl:value-of select="hm:RoomCount"/> 
       </roomcount> 
       <xsl:for-each select="hm:Occupancy "> 
        <guests> 
        <xsl:value-of select="sum((hm:AdultCount | hm:ChildCount)[number(.) = .])"/> 
        </guests> 
        <adults> 
        <xsl:value-of select="hm:AdultCount"/> 
        </adults> 
        <children> 
        <xsl:value-of select="hm:ChildCount"/> 
        </children> 
       </xsl:for-each> 
       </xsl:for-each> 
       <xsl:for-each select="hm:HotelRoom "> 
       <shrui> 
        <xsl:value-of select="@SHRUI"/> 
       </shrui> 
       <xsl:choose> 
        <xsl:when test="preceding-sibling::hm:HotelRoom[1]/@[email protected]"> 
        <noofroom>2</noofroom>      
        </xsl:when> 
        <xsl:otherwise> 
        <noofroom>1</noofroom> 
        </xsl:otherwise> 
       </xsl:choose> 
       <board> 
        <xsl:value-of select="hm:Board"/> 
       </board> 
       <roomtype> 
        <xsl:value-of select="hm:RoomType"/> 
       </roomtype> 
       <roomcode> 
        <xsl:value-of select="hm:RoomType/@code"/> 
       </roomcode> 
       <boardcode> 
        <xsl:value-of select="hm:Board/@code"/> 
       </boardcode> 
       <xsl:for-each select="hm:Price "> 
        <amount> 
        <xsl:value-of select="hm:Amount"/> 
        </amount> 
       </xsl:for-each> 
       </xsl:for-each> 
      </availableroom> 
      </xsl:for-each>

我的XML

<AvailableRoom> 
     <HotelOccupancy> 
      <RoomCount>1</RoomCount> 
      <Occupancy> 
      <AdultCount>1</AdultCount> 
      <ChildCount>0</ChildCount> 
      </Occupancy> 
     </HotelOccupancy> 
     <HotelRoom SHRUI="H6xFv7ejhSWcGuc+BCBYmg==" availCount="2" onRequest="N"> 
      <Board type="SIMPLE" code="FB-E10" shortname="FB">FULL BOARD</Board> 
      <RoomType type="SIMPLE" code="SGL-E10" characteristic="ST">SINGLE STANDARD</RoomType> 
      <Price> 
      <Amount>269.580</Amount> 
      </Price> 
     </HotelRoom> 
     </AvailableRoom> 
     <AvailableRoom> 
     <HotelOccupancy> 
      <RoomCount>1</RoomCount> 
      <Occupancy> 
      <AdultCount>1</AdultCount> 
      <ChildCount>0</ChildCount> 
      </Occupancy> 
     </HotelOccupancy> 
     <HotelRoom SHRUI="H6xFv7ejhSWcGuc+BCBYmg==" availCount="2" onRequest="N"> 
      <Board type="SIMPLE" code="FB-E10" shortname="FB">FULL BOARD</Board> 
      <RoomType type="SIMPLE" code="SGL-E10" characteristic="ST">SINGLE STANDARD</RoomType> 
      <Price> 
      <Amount>269.580</Amount> 
      </Price> 
     </HotelRoom> 
     </AvailableRoom>

來源

2013-07-29 Sirojan Gnanaretnam

我們需要查看XML結構的示例，以及您想要的結果和當前得到的結果。 –

嗨，我已經包含了我的XML。 –

在你的樣品HotelRoom元素都沒有兄弟姐妹，我想你想改變

<xsl:when test="preceding-sibling::hm:HotelRoom[1]/@[email protected]">

到

<xsl:when test="parent::hm:AvailableRoom/preceding-sibling::hm:AvailableRoom[1]/hm:HotelRoom/@[email protected]">

作爲HotelRoom元素是AvailableRoom元素的孩子是兄弟姐妹。

來源

2013-07-29 11:34:51

檢查上一個節點值的值並將當前值增加一個

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