無法訪問Codeigniter URL中的參數

Question

如何從Codeigniter網址獲取第三個參數，如http://domain.org/project/controller/view#tab-3/2。我需要訪問第三個參數值，即，在這裏，來自URL的2。我試過$this->uri->segment(3);，它沒有返回任何值。 $this->uri->segment(2);返回值view而不是view#tab-3。

我想要做的是CI中的分頁。在我的頁面中，我正在使用選項卡。在點擊TAB3它會調用一個Ajax功能，如下圖所示：

function receivedtickets(userid,baseurl) 
{ 
    var pagenum=$('#pagenum').val(); 

    if(pagenum!="" && pagenum!=undefined) 
    { 
     data='userid='+userid+'&pagenum='+pagenum; 
    } 
    else 
    { 
     data='userid='+userid; 
    } 
    $.ajax({ 
     type:'post', 
     url:baseurl+'video/receivedtickets/'+pagenum, 
     datatype:'json', 
     data:data, 
     success:function(response) 
     { 
      $('#tab-3').html(response.results); 
      $('#recpagination').html(response.pagination); 
     } 
    }); 
} 

pagenum是包含選項我的視圖頁面的隱藏字段。

if($this->uri->segment(3)) 
     { 
      $data['page_num']=$this->uri->segment(3); 
     } 
     else 
     { 
      $data['page_num']=0; 
     } 
<input type="hidden" id="pagenum" value="<?php echo $data['page_num'];?>"> 

的分頁控制器代碼：

function receivedtickets() 
    { 
     if (!$this->tank_auth->is_logged_in()) 
     {  // not logged in 
      redirect(base_url().'auth/login'); 
     } 
     $this->load->library('pagination');   // library for pagination 

     $userid=$_POST['userid']; 
     $per_pg=1; 

     if($this->uri->segment(3)) 
     { 
      $page_num= $this->uri->segment(3); 
      $offset=($page_num - 1) * $per_pg; 
     } 
     else 
     { 
      $offset=0; 
     } 

     $config['base_url'] = base_url().'video/tickets#tab-3'; 
     $config['total_rows'] = 50; 
     $config['div'] = '#pagination'; // div for displaying ajax 
     $config['per_page'] = $per_pg; 
     $config['uri_segment'] = 3; 
     $config['page_query_string'] = FALSE; 
     $config['use_page_numbers'] = TRUE; 
     $this->pagination->initialize($config); 
     $pagination=$this->pagination->create_links(); 

     $string=""; 
     $query=$this->db->query("SELECT 
    s.send_on, 
    s.sendby_id, 
    t.ticket_key, 
    t.video_id, 
    a.first_name, 
    a.last_name, 
    v.title, 
    v.videothumbnail , 
    s.sendto_id 
FROM 
    sendticket AS s 
    LEFT JOIN ticket AS t 
    ON s.ticketid = t.id 
    LEFT JOIN auth_user_profiles AS a 
    ON a.user_id = s.sendby_id 
    LEFT JOIN video AS v 
    ON t.video_id = v.videoid 
    WHERE (s.sendto_id = $userid or s.sendto_id ='gfhgfh@kgjgj.in') 
ORDER BY s.send_on DESC limit $offset,$per_pg"); 

     $string.='<div class="tableoutertb"> 
       <table class="myticketsdivv"> 
        <tr class="mytickets_row"> 
         <td class="mytickets_colmn ">'.lang('video').'</td> 
         <td class="mytickets_colmn ">'.lang('title').'</td> 
        </tr>'; 

        if($query->num_rows > 0) 
        { 
         foreach($query->result() as $row) 
         { 
          $string.='<tr class="mytickets_row"> 
          <td class="mytickets_colmn"> 
           <span class="mob_title">'.lang('video').'</span> 
           <a target="_blank" href="'.base_url().'video/playvideo/'.$row->video_id.'">'; 
            $string.='<img src="'.base_url().'images/No_image.png" style="max-width: 140px;" alt="Teshot featured video preview">'; 
           $string.='</a> 
          </td> 
          <td class="mytickets_colmn"> 
           <span class="mob_title">'.lang('title').'</span> 
           <a target="_blank" style="color: #3b5998;" href="'.base_url().'video/playvideo/'.$row->video_id.'">'.$row->title.'</a> 
          </td> 
          </tr>'; 
         } 
         $string.='<tr class="mytickets_row"><td class="mytickets_colmn" colspan="5"><div class="pagination" style="position: initial;margin-top:0px;float:right;" id="recpagination"></div></td></tr>'; 
        } 
       $string.='</table> 
       </div>'; 
       header('Content-type: application/json'); 
       $ret = array(); 
       $ret['results']=$string; 
       $ret['pagination']= $pagination; 
       echo json_encode($ret); 
     exit; 
    } 

誰能幫我解決這個問題？提前致謝。

Answer 1

哈希值（＃）後的值永遠不會發送到服務器 - 它在瀏覽器中消失，所以php（codeignitor）永遠不會知道它。

然而，似乎你只是訪問它，然後將其嵌入到頁面中，供js訪問。

相反，你可以直接與JS抓住從URL中的值：

function receivedtickets(userid,baseurl) 
{ 
    var hash = location.hash; 
    var pagenum = hash.substr(hash.lastIndexOf("/")+1); 

    if(pagenum!="" && pagenum!=undefined) 
    { 
     data='userid='+userid+'&pagenum='+pagenum; 
    } 
    else 
    { 
     data='userid='+userid; 
    } 
    $.ajax({ 
     type:'post', 
     url:baseurl+'video/receivedtickets/'+pagenum, 
     datatype:'json', 
     data:data, 
     success:function(response) 
     { 
      $('#tab-3').html(response.results); 
      $('#recpagination').html(response.pagination); 
     } 
    }); 
}