多維數組循環與一些值未設置 - PHP

Question

任何人都知道如何做到這一點？

我想通過一個數組，其中不是每個對象都有一個值。我想得到的是一個數組，其中的鍵保存了指定stdClass對象的數字，並將「value」作爲值。如果沒有指定「值」，則應打印「0」。

所以最後陣列應該是這個樣子：

Array ( 
[123456789_123456789] => 192 
[54321_98765] => 0 
[987654321_123456789] => 1292 
[987854321_123456734] => 0 
) 

原來這裏是輸出：

stdClass Object ( 
[123456789_123456789] => stdClass Object ( 
    [data] => Array ( 
     [0] => stdClass Object ( 
     [id] => 123456789_123456789/insights/name_of_metric/period 
     [name] => name_of_metric 
     [period] => lifetime 
     [values] => 
      Array ( 
       [0] => stdClass Object ( 
       [value] => 1292) 
       ) 
     [title] => Lifetime Post Organic Reach 
     [description] => A Description ... 
     [paging] => stdClass Object ( 
     [previous] => https://graph.facebook.com/ALINK 
     [next] => https://graph.facebook.com/ALINK 
)) 

[54321_98765] => stdClass Object ( 
    [data] => Array ( 

     [paging] => stdClass Object ( 
     [previous] => https://graph.facebook.com/ALINK 
     [next] => https://graph.facebook.com/ALINK 
)) 

[987654321_123456789] => stdClass Object ( 
    [data] => Array ( 
     [0] => stdClass Object ( 
     [id] => 987654321_123456789/insights/name_of_metric/period 
     [name] => name_of_metric 
     [period] => lifetime 
     [values] => 
      Array ( 
       [0] => stdClass Object ( 
       [value] => 1292) 
       ) 
     [title] => Lifetime Post Organic Reach 
     [description] => A Description ... 
     [paging] => stdClass Object ( 
     [previous] => https://graph.facebook.com/ALINK 
     [next] => https://graph.facebook.com/ALINK 
)) 

[987854321_123456734] => stdClass Object ( 
    [data] => Array ( 

     [paging] => stdClass Object ( 
     [previous] => https://graph.facebook.com/ALINK 
     [next] => https://graph.facebook.com/ALINK 
)) 
) 

這是我試過到目前爲止：

$aVar = array(); 
    foreach ($var as $var_1){ 
     foreach ($var_1->data as $var_2){ 
      foreach ($var_2->values as $var_3){ 
    $aVar[] = $var_3->value; 
     } 
    } 
} 

我相信我必須使用foreach (var_1->data as $var_2 => $var2_1)

Answer 1

的isset（）函數「語言結構」和is_array（）功能是你在這種情況下的朋友，除非你有沒有指定另外一個問題，你的問題不是很清楚;）

你需要什麼做的是中更改for-each循環外，以類似於以下的東西，有額外的驗證：

$aVar = array(); 
foreach ($var as $object_key=>$var_1) 
{ 
    if(isset($var_1->data) && is_array($var_1->data)) 
    { 
     foreach ($var_1->data as $var_2) 
     { 
      if(isset($var_2->values) && is_array($var_2->values)) 
      { 
       foreach ($var_2->values as $var_3) 
       { 
        $aVar[$object_key] = $var_3->value; 
       } 
      } 
     } 
    } 
} 

此代碼是未經測試，我不相信我所做的任何語法錯誤。