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我有以下Django模型:如何過濾ManyToManyField的記錄?
class TopicLabel(models.Model):
name = models.CharField(max_length=256)
order = models.IntegerField(null=True, blank=True)
topics = models.ManyToManyField(Topic, through='TopicLabelConnection')
class Topic(models.Model):
title = models.CharField(max_length=140)
visible = models.NullBooleanField(null=True, blank=True, default=False)
def __unicode__(self):
return self.title
class Meta:
verbose_name = _('topic')
verbose_name_plural = _('topics')
class TopicLabelConnection(models.Model):
topicId = models.ForeignKey(Topic, related_name='connection_topic')
labelId = models.ForeignKey(TopicLabel, related_name='connection_label')
def __unicode__(self):
return self.labelId.name + '/' + self.topicId.title
我想創建的TopicLabel
的方法,這將返回我TopicLabel.topic
集合中的所有題目,其中有Topic.visible = True
。
我想一個Django相當於下面的查詢方案:
SELECT *
FROM OPINIONS_TOPICLABELCONNECTION, OPINIONS_TOPIC
WHERE (OPINIONS_TOPICLABELCONNECTION.topicId_id = OPINIONS_TOPIC.id) AND
(OPINIONS_TOPICLABELCONNECTION.labelId_id = X) AND
(OPINIONS_TOPIC.visible = 1)
其中X
是主題標誌的主鍵。
我嘗試以下方法定義,它們都失敗:
1)
class TopicLabel(models.Model):
[...]
def getVisibleTopics():
return topics.filter(connection_topic__visible=True)
2)
class TopicLabel(models.Model):
[...]
def getVisibleTopics():
return topics.filter(visible=True)
3)
class TopicLabel(models.Model):
[...]
def getVisibleTopics():
return Topic.objects.filter(connection_label__visible=True).filter(connection_label__id=self.id)
4)
class TopicLabel(models.Model):
[...]
def getVisibleTopics():
return Topic.objects.filter(connection_label__visible=True).filter(connection_label__id=self.id)
5)
class TopicLabel(models.Model):
[...]
def getVisibleTopics():
return topics.filter(connection_topicId__visible=True)
什麼是正確的代碼?