請幫我找到我的編碼問題,我已經完成了所有AngularJS代碼以及用於json編碼的html和php,但無法獲取我的數據數據庫...這裏是我當前的代碼我已經完成了AngularJS代碼,但沒有顯示數據
的Index.html
<body ng-app="myApp" ng-controller="KaryawanCtrl">
<form method="post">
<input type="text" ng-model="karyawan.nama">
<input type="text" ng-model="karyawan.alamat">
<input type="submit" ng-click="tambahData()" value="simpan">
</form>
<table ng-init="dapatkanData()">
<thead>
<th>nama</th>
<th>alamat</th>
</thead>
<tr ng-repeat="item in dataKaryawan">
<td>{{item.nama}}</td>
<td>{{item.alamat}}</td>
</tr>
</table>
這裏是角碼
的js/app.js
var app= angular.module("myApp",[]);
app.controller("KaryawanCtrl",function($scope,$http){
//variabel awal
$scope.aksi="tambah";
$scope.karyawan={};
//angularjs untuk menyimpan data ke database
$scope.tambahData = function(){
$http.post(
'post.php',
{
data: $scope.karyawan
}
).success(function(data){
alert("data berhasil dimasukkan");
}).error(function(){
alert("Gagal menyimpan data");
});
//angularJS untuk menampilkan data ke tabel
$scope.dapatkanData = function(){
$http.get('karyawan.php').success(function(data){
$scope.dataKaryawan = data;
});
};
};
});
這裏是PHP
$koneksi = mysqli_connect("localhost","root","","belajar") or die("tidak bisa tersambung ke database");
$perintah_sql = "SELECT * FROM karyawan";
$data = [];
$result = mysqli_query($koneksi,$perintah_sql);
while($row= mysqli_fetch_array($result)){
$temp_data = [];
$temp_data['nama']= $row['nama'];
$temp_data['alamat']=$row['alamat'];
array_push($data,$temp_data);
}
echo json_encode($data);
你能告訴我們你得到的錯誤是什麼? –
嗨,就像我在標題中提到的,我的數據沒有顯示出來,當我訪問index.html ... –