將我的舊腳本轉換爲PDO結果不顯示？

Question

確定SI我不是很fimiliar與PDO我只是出發，可能有人幫助我在這裏，爲什麼我的成績將不顯示？頁面是工作，但沒有數據將顯示..

<?php   

require_once 'db/_db.php'; 
$stmt = $db->prepare("SELECT * FROM article"); 
$stmt->execute(); 
$result = $stmt->fetchAll(); 
$total_rows = $stmt->rowCount(); 

//$allRecords = mysql_query('select * from article'); 
//$total_rows = mysql_num_rows($allRecords);    

//$base_url = 'https://localhost/pagi/';    // 

    global $per_page;      

    $num_links = 4;       

    $total_rows = $total_rows; 

    $cur_page = 1;   

    if(isset($_GET['page'])) 
    { 
     $cur_page = $_GET['page']; 

     $cur_page = ($cur_page < 1)? 1 : $cur_page;   //if page no. in url is less then 1 or -ve 
    }    
$offset = ($cur_page-1)*$per_page;  //setting offset 
$pages = ceil($total_rows/$per_page); 
$start = (($cur_page - $num_links) > 0) ? ($cur_page - ($num_links - 1)) : 1; 
$end = (($cur_page + $num_links) < $pages) ? ($cur_page + $num_links) : $pages;  

    //$res = mysql_query("SELECT * FROM article ORDER BY id DESC LIMIT ".$per_page." OFFSET ".$offset);  

    $stm = $db->prepare("SELECT * FROM article ORDER BY id DESC LIMIT ".$per_page." OFFSET ".$offset); 

    $stm->execute(); 
    $res = $stm->fetchAll(); 
    $rows = $stm->rowCount(); 
    if($rows < 1){ 
     header("Location: news-events.php"); 
     exit; 
    }  

     if(is_resource($result)) 
     {  
      foreach($res as $row) {    

      $desc = $row["ne_article"]; 
      $img = $row['ne_image']; 
      if(!empty($img)){ 
      $img = '<br/><img src="uploads/images/'.$img.'" alt="" class="responsive-shrink">'; 
      }else{ 
      $img = ''; 
      } 
      $youtube = $row["ne_youtube"]; 

      if(!empty($youtube)){ 
      $youtube = '<br/><div class="video-container"><iframe src="http://www.youtube.com/embed/'.$youtube.'"></iframe></div>'; 
      }else{ 
      $youtube = ''; 
      } 
      //shortenString($row['ne_article']); 
     ?> 

      <h4><a href="<?php echo $row['ne_url']; ?>"><?php echo $row['ne_title']; ?></a></h4> 

      <h5><b>Views:</b> <?php echo $row['views']; ?>, <b>Posted on:</b> <?php echo format_date($row['created']); ?></h5>     

      <?php echo $img; ?> 

      <?php echo $youtube; ?> 

      <p> 

      <br/><?php echo bbcode(nl2br(shortenString($desc))); ?> 

      </p> 

      <div id="pagelink"> 

       <a href="<?php echo $row['ne_url']; ?>" class="myButton"> Read more...</button></a> 
       </div> 
     <?php 
      } 
     } 
     ?> 


    <div id="pagination"> 
    <div id="pagiCount"> 
    <br/><br/> 
     <?php 

      if(isset($pages)) 
      { 
       if($pages > 1)  
       { if($cur_page > $num_links)  // for taking to page 1 // 
        { $dir = "First"; 
         echo '<span id="prev"> <a href="'.$_SERVER['PHP_SELF'].'?page='.(1).'">'.$dir.'</a> </span>'; 
        } 
        if($cur_page > 1) 
        { 
         $dir = "Prev"; 
         echo '<span id="prev"> <a href="'.$_SERVER['PHP_SELF'].'?page='.($cur_page-1).'">'.$dir.'</a> </span>'; 
        }           

        for($x=$start ; $x<=$end ;$x++) 

        {       

         echo ($x == $cur_page) ? '<strong>'.$x.'</strong> ':'<a href="'.$_SERVER['PHP_SELF'].'?page='.$x.'">'.$x.'</a> '; 
        } 
        if($cur_page < $pages) 

        { $dir = "Next"; 

         echo '<span id="next"> <a href="'.$_SERVER['PHP_SELF'].'?page='.($cur_page+1).'">'.$dir.'</a> </span>'; 
        } 

        if($cur_page < ($pages-$num_links)) 
        { $dir = "Last";      

         echo '<a href="'.$_SERVER['PHP_SELF'].'?page='.$pages.'">'.$dir.'</a> '; 
        } 

       } 

      } 

     ?> 

將非常感謝您的時間和幫助

Answer 1

你正在做的幾乎所有錯誤。並且你也使用舊的mysql以及

要獲取數據庫中的記錄數量，您應該從不選擇所有行，也不要獲取它們。你必須選擇計數。

$total_rows = $pdo->query("SELECT count(1) FROM article")->fetchColumn(); 

是如何使用PDO完成的。

此外，對於其他查詢，你應該使用準備語句。
最後，你必須拿出所有的無用的驗證，並與foreach馬上開始：

$stm = $db->prepare("SELECT * FROM article ORDER BY id DESC LIMIT ?,?"); 
$stm->execute([$offset,$per_page]); 
$res = $stm->fetchAll(); 
foreach($res as $row) {    

而上正常here設置錯誤模式閱讀起來。

Answer 2

檢查，如果你有引號...當你內部回聲「HTML代碼」，如果你有「」，並再次「」內，像這樣的例子回聲「‘‘’’」您將有問題的問題。你應該使用\'以避免這些問題echo''。$ dir。' 「;