如何比較兩個查詢結果在同一個循環

Question

我有2 sql queries（每個一個學期）。這兩個查詢不具有相同的行數。每個包含3個參數：Article id_Customer Turnover。

這以下，其計算第一學期的請求：

select "LRU", "Client", round(sum("Montant_fac_eur")) 
from "foundry_sync"."data" 
where "Nature"='Repair'  

and extract(month from "Facturation") between 0+{{w_widget6.selectedValue}} and 5+{{w_widget6.selectedValue}} 
group by "LRU", "Client" 

查詢的學期表示這樣的：

{ 
    "LRU": [ 
    "ATSU", 
    "ATSU", 
    "ATSU", 
    "ATSU 
     . 
     . 
     . 
    ], 
"Client": [ 
    394, 
    594, 
    4001, 
    5725, 
    7057, 
    7090 
    . 
    . 
    . 
], 
"round": [ 
    20866, 
    16814, 
    27421, 
    0, 
    6593, 
    66965, 
    8401 
    . 
    . 
    . 
] 

這以下的結果的一個示例：

result 1      result2 

"[Article1,394,3914]"  "[Article1,394,3914]" 
"[Article1,594,16814]"  "[Article2,594,10088]" 
"[Article1,4001,26798]" "[Article1,4001,11107]" 
"[Article3,5725,0]"  "[Article3,5725,0]" 
"[Article5,7057,5700]"  "[Article5,7057,3916]" 
"[Article8,7090,56467]" "[Article4,7090,17558]" 
"[Article2,7236,8401]"  "[Article8,7236,8401]" 
"[Article11,7242,12766]" "[Article14,7242,4255]" 
"[Article2,7262,892]"  "[Article2,7262,892]" 
"[Article3,7302,17234]" "[Article3,7302,8928]" 

如您所見，客戶可以在兩個學期或一個學期僅在一個學期（第一個或第二個）的文章營業額。 我想首先比較每個學期每個customer每個Article的營業額。

var query1 = {{repair_semestre1}}; 
    var query2 = {{repair_semestre2}}; 
    var result1 = []; 
    var result2 = []; 


    for (var i = 0; i < query1.LRU.length; i++) { 
     result1.push(formatName(query1.LRU[i], query1.Client[i], query1.round[i])); 
    } 

    for (var i = 0; i < query2.LRU.length; i++) { 
     result2.push(formatName(query2.LRU[i], query2.Client[i], query2.round[i])); 
    } 

    return { 
     result1: result1, 
     result2: result2 
    }; 

    /* for (var i = 0; i < query1.LRU.length, i < query2.LRU.length; i++) { 
     if((query1.LRU[i] == query2.LRU[i]) && (query1.Client[i] == query2.Client[i])) { 
        if(query1.round[i] > query2.round[i]) { 
          return "ok"; 
        } 
        else { return "non"; 
        } 
     } 

    } */ 

    function formatName(lru, turnover, round) { 
     return "[" + lru + "," + turnover + "," + round + "]"; 
    } 

我做了一個循環的功能外，這些2個查詢比較她的結果：

var query1 = {{repair_semestre1}}; 
var query2 = {{repair_semestre2}}; 
for (var i = 0; i < query1.LRU.length, i < query2.LRU.length; i++) { 
    if((query1.LRU[i] == query2.LRU[i]) && (query1.Client[i] == query2.Client[i])) { 
       if(query1.round[i] > query2.round[i]) { 
         return "ok"; 
       } 
       else { return "not ok"; 
       } 
    } 
} 

它僅返回not ok，不完成行的其餘部分。可以請你解釋一下爲什麼？ 如何在我的函數中添加這個循環來運行？

謝謝。

Answer 1

我建議首先將您的數據結構轉換爲將相關內容在一個對象中組合在一起的東西，而不是與索引編號鏈接。

例如，對於客戶端594，誰是參與的兩篇文章，這學期轉旁白可以這樣表示：

{ 
    "594": { 
    "Article1": [ 
     16814, 
     0 
    ], 
    "Article2": [ 
     0, 
     10088 
    ] 
    } 
} 

...其中內陣列始終有兩個入口：每個的兩個學期。該結構將允許輕鬆報告。

這裏是以下這對於例如輸出轉換的代碼：

// Sample data 
 
const query1 = { 
 
    LRU: ["Article1", "Article1", "Article1", "Article3", "Article5", 
 
      "Article8", "Article2", "Article11", "Article2", "Article3"], 
 
    Client: [394, 594, 4001, 5725, 7057, 7090, 7236, 7242, 7262, 7302], 
 
    round: [3914, 16814, 26798, 0, 5700, 56467, 8401, 12766, 892, 17234] 
 
}, query2 = { 
 
    LRU: ["Article1", "Article2", "Article1", "Article3", "Article5", 
 
      "Article4", "Article8", "Article14", "Article2", "Article3"], 
 
    Client: [394, 594, 4001, 5725, 7057, 7090, 7236, 7242, 7262, 7302], 
 
    round: [3914, 10088, 11107, 0, 3916, 17558, 8401, 4255, 892, 8928] 
 
}; 
 

 
// Convert to a more useful data structure, keyed by client and article 
 
const data = {}; 
 
[query1, query2].forEach(function (query, semester) { 
 
    query.Client.forEach(function(clientId, index) { 
 
     var client = data[clientId] = data[clientId] || {}; 
 
     var clientArt = client[query.LRU[index]] = client[query.LRU[index]] || [0, 0]; 
 
     clientArt[semester] = query.round[index]; 
 
    }); 
 
}); 
 

 
// Now report on that data 
 
for (const client in data) { 
 
    for (const article in data[client]) { 
 
     const turnovers = data[client][article]; 
 
     console.log('Client: ' + client + ', art.: ' + article 
 
        + ', semester t/o: ' + turnovers 
 
        + ' ' + (turnovers[0] === turnovers[1] ? 'equal' : 
 
          turnovers[0] < turnovers[1] ? 'increase' : 
 
                 'decrease')); 
 
    } 
 
}

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