我正在做一個應用程序,它從Web服務獲取JSON數據並在SQLite數據庫中進行更新。我的問題是我從Web服務獲得的價值,但上傳時顯示'空'。它沒有得到更新。Sqlite數據庫不會更新來自Web服務的數據
我的代碼: -
-(void) updateSignupTable: (NSDictionary*) json {
//copying the values from web services
NSString *balance = [json objectForKey:@"balance"];
NSString *phone_number =[json objectForKey:@"sim_number"];
NSString *call_forward_Status = [json objectForKey:@"call_forward_status"];
//在數據庫中存儲它
sqlExecutObj.sql=[NSString stringWithFormat:@"UPDATE profile_table SET phone_number ='%@' balance = '%@' call_forward_status = '%@' WHERE profile_name= '%@'", phone_number ,balance, call_forward_Status, profileDetailTitle];
sqlExecutObj.dataTypeArray=[[NSMutableArray alloc]initWithObjects:@"1",@"1",@"1",nil];
[sqlExecutObj executeSelectQuery];
///reloading the table
[profileDetailView.detailsTableView reloadData];
// fetch and print the updated datas from SQLite
sqlExecutObj.sql=[NSString stringWithFormat:@"SELECT call_forward_status,phone_number,balance FROM profile_table WHERE profile_name= '%@'",selectedProfileName];
sqlExecutObj.dataTypeArray=[[NSMutableArray alloc]initWithObjects:@"1",@"1",@"1",nil];
[sqlExecutObj executeSelectQuery];
NSLog(@"result from table are: %@. and %@, and %@", [[sqlExecutObj.result objectAtIndex:0] objectAtIndex:0],[[sqlExecutObj.result objectAtIndex:1] objectAtIndex:0],[[sqlExecutObj.result objectAtIndex:2]objectAtIndex:0]);
}
我調試輸出: -
2013-05-14 15:54:02.910 Movirtu[44262:19d03] result from table are: (null). and (null), and (null)
什麼是'sqlExecuteObj'?你爲什麼使用'executeSelectQuery'來執行'UPDATE'? – trojanfoe 2013-05-14 10:36:47
sqlExecute.obj是SQLite類中的一個變量,我在SQLite.h中使用它,executeQuery是執行sqlExecuteobj.sql保存的查詢的方法。 – Logunath 2013-05-14 10:39:27
我使用了相同的過程來存儲任何靜態變量在我的代碼的不同位置,它的工作原理,但聽到它不工作。 – Logunath 2013-05-14 10:40:34