如何得到由

在與組所需的輸出MongoDB的排序查詢是具有記錄等我的MongoDB集合...如何得到由

{"type":"ORDER_PLACE", "price":100, "emailId":"[email protected]"} 
{"type":"CART_ORDER", "price":150, "emailId":"[email protected]"} 
{"type":"ORDER_PLACE", "price":200, "emailId":"[email protected]"} 
{"type":"CART_ORDER", "price":350, "emailId":"[email protected]"} 
{"type":"CART_ORDER", "price":250, "emailId":"[email protected]"} 
{"type":"ORDER_PLACE", "price":240, "emailId":"[email protected]"} 
{"type":"ORDER_PLACE", "price":330, "emailId":"[email protected]"}

我想要的結果應該是這樣......

{"emailId":"[email protected]", "type":"ORDER_PLACE", "total":540} 
{"emailId":"[email protected]", "type":"ORDER_PLACE", "total":330}

什麼將是排序查詢來獲得上面的結果（desc order）。

來源

2017-03-22 Rama Krishna

這裏是查詢，讓您導致您的結構：

db.coll.aggregate([{$match: {type: "ORDER_PLACE"}}, {$group: {_id: "$emailId", total: {$sum: "$price"}}},{$project:{_id:0,emailId:"$_id",type:"ORDER_PLACE",total:"$total"}}])

來源

2017-03-22 13:43:34 iskramac

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