For循環與陣列不打印正確的結果

Question

新的js，代碼如下。在這裏，我無法打印正確的結果。我認爲+ "names[i]"這部分代碼有問題。

var names = ["aha","mk", "jk","hk","fhf"]; 
for (i=1;i<=names.length;i++){ 
    console.log("I know someone called "+ "names[i]"); 
    } 

Answer 1

省略名稱[i]周圍的引號。 它應該是：所有的

var names = ["aha","mk", "jk","hk","fhf"]; 
for (i=1;i<=names.length;i++){ 
    console.log("I know someone called "+ names[i]); 
} 

Answer 2

var names = ["aha","mk", "jk","hk","fhf"]; 
for (i=1;i<=names.length;i++){ 
    console.log("I know someone called "+ names[i]); 
    } 

名[i]是一個字符串了。

Answer 3

• FIRST：正如大家一直說，你不要放置names[i]雙引號內，因爲它是一個定義的變量的引用。

• 第二：在您的for循環的** ** 聲明i<=names.length，但它應該是i<names.length。你的方式會一路走到6，這太高了。

• 第三：除了第二個錯誤，你也必須改變names[i]到names[i--]，因爲i<names.length仍然會達到5和1過高了一些，開始用的。

Answer 4

不加引號使用names[i]它是一個expression提供你的價值觀

，您可以利用的es6模板串

var names = ["aha","mk", "jk","hk","fhf"]; 
    for (i=0;i<=names.length-1;i++){ 
     console.log(`I know someone called ${names[i]}`); 
    } 

Answer 5

請檢查名稱[I]不應該保持雙引號，並將i值更改爲0

var names = ["aha","mk", "jk","hk","fhf"]; 
for (i=0;i<=names.length;i++) 
{ 
     console.log("I know someone called "+ names[i]); 
} 

Answer 6

我認爲這是工作正確 您需要刪除=符號並設置i = 0

var names = ["aha","mk", "jk","hk","fhf"]; 
     for (i=0;i<names.length;i++){ 
     console.log("I know someone called "+ names[i]); 
    }