發送光標像素

Question

我試圖找到一種方法將光標發送到屏幕上的像素的正方形廣場。在這裏，我有一些代碼，可以將它發送到特定位置：

package JavaObjects; 
import java.awt.AWTException; 
import java.awt.Robot; 

public class MCur { 
    public static void main(String args[]) { 
     try { 
      // The cursor goes to these coordinates 
      int xCoord = 500; 
      int yCoord = 500; 

      // This moves the cursor 
      Robot robot = new Robot(); 
      robot.mouseMove(xCoord, yCoord); 
     } catch (AWTException e) {} 
    } 
} 

有可能是某種方式，使用類似的代碼，我可以建立一個範圍，而不是一個特定的點，使得光標去建立廣場的一些隨機部分？

Answer 1

既然你跟你說一個「廣場」的工作，你可能想使用java.awt.Rectangle中的類，如果你點擊按鈕，這是非常有用的，你可以定義按鈕的邊界，而不是一個點。

至於隨機半徑，這是很容易與java.util.Random的

import java.awt.AWTException; 
import java.awt.Dimension; 
import java.awt.Rectangle; 
import java.awt.Robot; 
import java.awt.Toolkit; 
import java.util.Random; 

public class MoveMouse { 

    private static final Robot ROBOT; 
    private static final Random RNG; 

    public static void main(String[] args) { 
     // grab the screen size 
     Dimension screen = Toolkit.getDefaultToolkit().getScreenSize(); 
     // Equivalent to 'new Rectangle(0, 0, screen.width, screen.height)' 
     Rectangle boundary = new Rectangle(screen); 
     // move anywhere on screen 
     moveMouse(boundary); 
    } 

    public static void moveMouse(int x, int y, int radiusX, int radiusY) { 
     Rectangle boundary = new Rectangle(); 
     // this will be our center 
     boundary.setLocation(x, y); 
     // grow the boundary from the center 
     boundary.grow(radiusX, radiusY); 
     moveMouse(boundary); 
    } 

    public static void moveMouse(Rectangle boundary) { 
     // add 1 to the width/height, nextInt returns an exclusive random number (0 to (argument - 1)) 
     int x = boundary.x + RNG.nextInt(boundary.width + 1); 
     int y = boundary.y + RNG.nextInt(boundary.height + 1); 
     ROBOT.mouseMove(x, y); 
    } 

    // initialize the robot/random instance once when the class is loaded 
    // and throw an exception in the unlikely scenario when it can't 
    static { 
     try { 
      ROBOT = new Robot(); 
      RNG = new Random(); 
     } catch (Exception e) { 
      throw new RuntimeException(e); 
     } 
    } 

} 

完成這是一個基本的演示。

您可能需要添加負/外的範圍值檢查等，以便它不會嘗試單擊關閉屏幕。