如何找到關鍵字在谷歌上的位置與PHP

Question

如何找到我在PHP上的關鍵字位置？

我想這個網址：

http://www.google.com/url?sa=t&source=web&ct=res&cd=7&url=http%3A%2F%2Fwww.example.com%2Fmypage.htm&ei=0SjdSa-1N5O8M_qW8dQN&rct=j&q=flowers&usg=AFQjCNHJXSUh7Vw7oubPaO3tZOzz-F-u_w&sig2=X8uCFh6IoPtnwmvGMULQfw

，但我無法得到任何的HTML源代碼。

我該怎麼做？

Answer 1

也許你應該只用於此用途寫的一類，例如this one on github

Answer 2

我使用這個腳本我做了。 因爲它依賴於可能來自谷歌改變HTML時，它是不可靠的，但確實它的工作現在：

<?php 

    // Include the phpQuery library 
    // Download at http://code.google.com/p/phpquery/ 
    include("phpQuery-onefile.php"); 

    $country = "en"; 
    $domain = "stackoverflow.com"; 
    $keywords = "php google keyword rank checker"; 
    $firstnresults = 50; 

    $rank = 0; 
    $urls = Array(); 
    $pages = ceil($firstnresults/10); 
    for($p = 0; $p < $pages; $p++){ 
     $start = $p * 10; 
     $baseurl = "https://www.google.com/search?hl=".$country."&output=search&start=".$start."&q=".urlencode($keywords); 
     $html = file_get_contents($baseurl); 

     $doc = phpQuery::newDocument($html); 

     foreach($doc['#ires cite'] as $node){ 
      $rank++; 
      $url = $node->nodeValue; 
      $urls[] = "[".$rank."] => ".$url; 
      if(stripos($url, $domain) !== false){ 
       break(2); 
      } 
     } 
    } 

    print "Country: ".$country."\n"; 
    print "Domain: ".$domain."\n"; 
    print "Keywords: ".$keywords."\n"; 
    print "Rank: ".$rank."\n"; 
    print "First urls:\n"; 
    print implode("\n", $urls)."\n"; 

?>