丟失記錄在SQL Server 2008R2

Question

表1：

Date   PlacementID  CampaignID Impressions 
04/01/2014  100    10   1000 
04/01/2014  101    10   1500 
04/01/2014  100    11   500 

表2：

Date   PlacementID  CampaignID Cost 
04/01/2014  100    10   5000 
04/01/2014  101    10   6000 
04/01/2014  100    11   7000 
04/01/2014  103    10   8000 

當我加入使用全部加入和左連接聲明此表，我不能以獲得不常見的記錄，這是table2中顯示PlacementID 103和CampaignID 10和Cost 8000的最後一行。但是我已經搜索了所有原始數據和文件，但是這兩個數據源之間缺少記錄是不常見的。但是，我希望將這些記錄包含在決賽桌中。我怎樣才能做到這一點？這兩個表是兩個不同的來源，我得到的結果只有常見的記錄。

此外，當我發現缺失值是精確值，這是最終數字所要求的，所以要包括每一件事情。我包括我下面的SQL腳本：

SELECT A.palcementid, 
     A.campaignid, 
     A.date, 
     Sum(A.impressions) AS Impressions, 
     Sum(CASE 
      WHEN C.placement_count > 1 THEN (B.cost/C.placement_count) 
      ELSE B.cost 
      END)   AS Cost 
FROM table1 A 
     FULL JOIN table2 B 
       ON A.placementid = B.placementid 
       AND A.campaignid = B.campaignid 
       AND A.date = B.date 
     LEFT JOIN (SELECT Count(A.placementid) AS Placement_Count, 
         placementid. campaignid, 
         date 
        FROM table1 
        GROUP BY placementid, 
          campaignid, 
          date) c 
       ON A.placementid = C.placementid 
       AND A.campaignid = C.campaignid 
       AND A.date = C.date 
GROUP BY A.placementid, 
      A.campaignid, 
      A.date 

我除以安置成本，因爲在源成本被分配只有一個位置和一個時間，所以我必須分配的，因爲在實際的表一樣Placementid重複多比同日期的1倍多。

Answer 1

由於您沒有提供任何期望的輸出我猜在這裏，但如果你想要的結果是這樣的：

PlacementID CampaignID Date     Impressions Cost 
----------- ----------- ----------------------- ----------- ----------- 
100   10   2014-04-01 02:00:00.000 1000  5000 
100   11   2014-04-01 02:00:00.000 500   7000 
101   10   2014-04-01 02:00:00.000 1500  6000 
103   10   2014-04-01 02:00:00.000 NULL  8000 

然後下面的查詢應該這樣做：

SELECT COALESCE(A.PlacementID,b.placementid) AS PlacementID, 
     COALESCE(A.campaignid, b.campaignid) AS CampaignID, 
     COALESCE(A.date, b.date) AS [Date], 
     SUM(A.impressions) AS Impressions, 
     SUM(CASE 
      WHEN C.placement_count > 1 THEN (B.cost/C.placement_count) 
      ELSE B.cost 
      END) AS Cost 
FROM table1 A 
     FULL JOIN table2 B 
       ON A.[PlacementID] = B.placementid 
       AND A.campaignid = B.campaignid 
       AND A.date = B.date 
     LEFT JOIN (SELECT COUNT(PlacementID) AS Placement_Count, 
         placementid, campaignid, 
         date 
        FROM table1 
        GROUP BY placementid, 
          campaignid, 
          date) c 
       ON A.[PlacementID] = C.placementid 
       AND A.campaignid = C.campaignid 
       AND A.date = C.date 
GROUP BY COALESCE(A.PlacementID, B.PlacementID), 
      COALESCE(A.campaignid, b.campaignid), 
      COALESCE(A.date, b.date) 

樣品SQL Fiddle