PHP array_search

Question

是否有任何函數可以完成數組$ array的等價操作？像，這將是一個理想的解決方案：

$needle = array('first', 'second'); 
$haystack = array('fifth','second','third', 'first'); 

// Returns key 1 in haystack 
$search = array_search($needle, $haystack); 

如果沒有的功能，接受針任何其他功能，這可能是我可以用它來創建自定義函數數組？

Answer 1

這可能有助於建立你的函數：

$intersection = array_intersect($needle, $haystack); 

if ($intersection) // $haystack has at least one of $needle 

if (count($intersection) == count($needle)) // $haystack has every needle 

Answer 2

您可以使用array_intersect（）：http://php.net/manual/en/function.array-intersect.php

if (empty(array_intersect($needle, $haystack)) { 
    //nothing from needle exists in haystack 
} 

Answer 3

$needle = array('first', 'second'); 
$haystack = array('fifth','second','third', 'first'); 

// Returns key 1 in haystack 


function array_needle_array_search($needle, $haystack) 
{ 
     $results = array(); 
     foreach($needle as $n) 
     { 
       $p = array_search($n, $haystack); 
       if($p) 
        $results[] = $p; 
     } 
     return ($results)?$results:false; 
} 

print_r(array_needle_array_search($needle, $haystack)); 

Answer 4

$needle = array('first', 'second'); 
$haystack = array('fifth','second','third', 'first'); 

if(in_array($needle, $haystack)) { 
    echo "found"; 
}