0
我試圖發送JSON數據使用jQuery的AJAX調用servlet中...以下是代碼從JavaScript發送JSON數據到Java
$(function() {
$("#mybutton").click(function() {
var testdata = JSON.stringify({
'name': 'name',
'desc':'test'
});
$.ajax({
type: "POST",
url:"/Alert/ReportServlet",
data: testdata,
dataType: "json",
contentType: "application/json",
success : function(data){
console.log("success:", data);
},
error : function(data) {
console.log("error:", data);
}
});
});
});
和servlet代碼是
public class ReportingServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException {
System.out.println("The data is" + request.getParameter("testdata"));
}
}
該值來作爲空...請建議
可能重複[在Java Servlet中通過jquery ajax發送參數](http://stackoverflow.com/questions/19374345/get-parameter-sent-via-jquery-ajax-in-java-servlet) – Hirak
向我們展示'web.xml '用於servlet映射。在你的代碼中,url是'/ Alert/ReportServlet',而服務器類名是'ReportingServlet'。 –
請使用request.getQueryString(),因爲您發送了「{'name':'name','desc':'test'}」到後端,沒有任何參數叫testdata –