3
的CloudCode功能是:解析CloudCode功能不起作用。調用它時我得到一個錯誤
Parse.Cloud.define('addFriend', function(request, response) {
var userId = request.params.userId;
var User = Parse.Object.extend('_User'),
user = new User({ objectId: userId });
var currentUser = request.user;
var relation = user.relation("Friends");
relation.add(currentUser);
Parse.Cloud.useMasterKey();
user.save().then(function(user) {
response.success(user);
}, function(error) {
response.error(error)
});
});
當我與PFCloud電話呼叫從Xcode中....我得到下一個錯誤在我的控制檯:
[Error]: ReferenceError: parent is not defined
at e.n.value (Parse.js:13:7510)
at main.js:10:14 (Code: 141, Version: 1.8.2)
這意味着實際的問題是關係沒有父母。它應該已經有'用戶'變量作爲父項,因爲我調用user.relation(「好友」),這就是文檔所說的:「你很少應該手動設置父項,因爲你很可能打電話給Parse.Object.relation( '鍵')。」這是我正在做的。
UPDATE
即使是這個代碼是給予相同的錯誤:
Parse.Cloud.define("addFriend", function(request, response) {
Parse.Cloud.useMasterKey();
var currentUser = request.user;
var relation = currentUser.relation("Friends");
relation.add(currentUser);
});
更新2:
用戶JSON
{
"FriendRequests": {
"__type": "Relation",
"className": "_User"
},
"Friends": {
"__type": "Relation",
"className": "_User"
},
"createdAt": {
"__type": "Date",
"iso": "2015-09-10T17:29:03.181Z"
},
"sessionToken": "r:KkmTu7xRjTEFpl0vcANVf0xXH",
"updatedAt": {
"__type": "Date",
"iso": "2015-09-10T17:29:03.181Z"
},
"username": "bogdan12",
"objectId": "BmbNRxCyau"
}
RELA重刑JSON
{
"__type": "Relation",
"className": "_User"
}
它不工作。 –
在編輯關係之前,您可能需要首先獲取用戶。 – deadbeef
這是否也是...同樣的錯誤 –