轉換JSON字符串PHP數組，然後使用PHP數組

Question

進出口新的JSON & PHP和我有使用JSON一些問題納入PHP字符串

我的JSON字符串看起來像這樣

{"status":"OK","cards": 
[{"id":100001,"name":"batman","image":11111,"size":75,"region_id":1,"locked":false,"status":"active","created_at":"2013-08-15T11:37:07Z"}, 
{"id":100002,"name":"superman","image":111111,"size":75,"region_id":1,"locked":false,"status":"active","created_at":"2013-08-15T12:30:09Z"}, 
{"id":100003,"name":"catwoman","image":1111111,"size":75,"region_id":1,"locked":false,"status":"active","created_at":"2013-08-15T12:39:42Z"}, 
{"id":100004,"name":"bane","image":1111111,"size":75,"region_id":1,"locked":false,"status":"active","created_at":"2013-09-08T12:56:04Z"} 
]} 

到目前爲止我創建了我的字符串

$json_raw = '{"status":"OK","cards": [{"id":100001,"name": ..... 

解碼的JSON

$arr = json_decode($json_raw, TRUE); 

I var_dump（$ arr）;

然後返回

array(2) { ["status"]=> string(2) "OK" ["cards"]=> array(4) { [0]=> array(8) { ["id"]=> int(100001) ["name"]=> string(6) "batman" ["image"]=> int(11111) ["size"]=> int(75) ["region_id"]=> int(1) ["locked"]=> bool(false) ["status"]=> string(6) "active" ["created_at"]=> string(20) "2013-08-15T11:37:07Z" } [1]=> array(8) { ["id"]=> int(100002) ["name"]=> string(8) "superman" ["image"]=> int(111111) ["size"]=> int(75) ["region_id"]=> int(1) ["locked"]=> bool(false) ["status"]=> string(6) "active" ["created_at"]=> string(20) "2013-08-15T12:30:09Z" } [2]=> array(8) { ["id"]=> int(100003) ["name"]=> string(8) "catwoman" ["image"]=> int(1111111) ["size"]=> int(75) ["region_id"]=> int(1) ["locked"]=> bool(false) ["status"]=> string(6) "active" ["created_at"]=> string(20) "2013-08-15T12:39:42Z" } [3]=> array(8) { ["id"]=> int(100004) ["name"]=> string(4) "bane" ["image"]=> int(1111111) ["size"]=> int(75) ["region_id"]=> int(1) ["locked"]=> bool(false) ["status"]=> string(6) "active" ["created_at"]=> string(20) "2013-09-08T12:56:04Z" } } } 

現在我想做的是能夠使用這個數據

例如，如果名稱=蝙蝠俠然後

我知道這是一個愚蠢的問題，但我我掙扎着:(

在此先感謝

Answer 1

json_decode()與TRUE作爲第二個參數給你一個關聯數組。你需要訪問正確的索引來做你想做的事。

要列出好的格式完整的關聯數組，你可以這樣做：

echo '<pre>', print_r($arr), '</pre>'; 

現在，訪問name數組中：

$man = $arr['cards'][0]['name']; 

要檢查它是否是Batman（耶！）：

if(isset($man) && $man == 'batman') { 
    # code ... 
} 

爲了讓所有的類似名稱的名稱：

$man = $json['cards']['0']['name']; 
for ($i=0; $i < count($json['cards']); $i++) { 
    echo $json['cards'][$i]['name']."\n"; 
} 

See it live!

Answer 2

嘗試用：

$cards = $arr['cards']; 
foreach($cards as $card) { 
    if($card['name'] == 'batman') echo 'Hello batman!'; 
} 

編輯：

好了，所以這爲我工作usi納克以上代碼，自己嘗試一下，如果你想：

<?php 

$json_raw = '{"status":"OK","cards": 
[{"id":100001,"name":"batman","image":11111,"size":75,"region_id":1,"locked":false,"status":"active","created_at":"2013-08-15T11:37:07Z"}, 
{"id":100002,"name":"superman","image":111111,"size":75,"region_id":1,"locked":false,"status":"active","created_at":"2013-08-15T12:30:09Z"}, 
{"id":100003,"name":"catwoman","image":1111111,"size":75,"region_id":1,"locked":false,"status":"active","created_at":"2013-08-15T12:39:42Z"}, 
{"id":100004,"name":"bane","image":1111111,"size":75,"region_id":1,"locked":false,"status":"active","created_at":"2013-09-08T12:56:04Z"} 
]}'; 


$arr = json_decode($json_raw, TRUE); 

$cards = $arr['cards']; 
foreach($cards as $card) { 
    if($card['name'] == 'batman') echo 'Hello batman!'; 
} 

?> 

Answer 3

當你得到了數組

$arr = json_decode($json_raw, TRUE); 

然後檢查卡鑰匙存在

if(array_key_exists('cards', $arr)){ 
    foreach($arr['cards'] as $key=>$val){ 

    echo $key; ///name, id.. 
    echo $val; /// batman,... 
    if($key == 'name' && $val =='batman'){ 
     //-------do your stuff 
    } 
    } 
}