有條件地添加多個孩子XElements

Question

我能夠使用下面的代碼有條件地添加一個孩子xelement，但是當我嘗試添加多個元素時，我得到語法警告。我怎樣才能添加多個？

OK

new XElement("AllNumbers", 
       bonusNumbers.Any() ? 
       from n in bonusNumbers select 
       new XElement("BonusNumbers", bonusNumbers.ToArray()) 
       :null), 

不正常

new XElement("AllNumbers", 
       numbers.Any() ? 
       from n in numbers select 
       new XElement("Numbers", numbers.ToArray()) 
       :null; 

       bonusNumbers.Any() ? 
       from n in bonusNumbers select 
       new XElement("BonusNumbers", bonusNumbers.ToArray()) 
       :null), 

Answer 1

new XElement("AllNumbers", 
    numbers.Any() ? 
    from n in numbers 
    select new XElement("Numbers", numbers.ToArray()) 
    : null, // should be , instead of ; 

    bonusNumbers.Any() ? 
    from n in bonusNumbers 
    select new XElement("BonusNumbers", bonusNumbers.ToArray()) 
    : null); 

順便說一下它不清楚爲什麼要添加的所有號碼在收集每個號碼。如果你希望把自己的元素每個號碼

new XElement("AllNumbers", 
    numbers.Any() ? new XElement("Numbers", numbers) : null, 
    bonusNumbers.Any() ? new XElement("BonusNumbers", bonusNumbers) : null); 

或者：

new XElement("AllNumbers", 
    numbers.Any() ? 
     new XElement("Numbers", 
      numbers.Select(n => new XElement("Number", n))) : null, 
    bonusNumbers.Any() ? 
     new XElement("BonusNumbers", 
      bonusNumbers.Select(n => new XElement("Number", n))) : null);