2016-11-16 55 views
0

這裏是我的代碼來編寫我的xml代碼。此XML代碼我正在將兩個表來獲取特定格式爲我的XML用XML文件中的數據填充datagridview。編輯並保存回XML C#

using (XmlWriter xmlWriter = XmlWriter.Create(path, xmlWriterSettings)) 
{ 
    xmlWriter.WriteStartElement("Address"); 
    xmlWriter.WriteStartElement("Work"); 
    foreach (DataRow dataRow in dt.Rows) 
    { 
     xmlWriter.WriteStartElement("MD"); 
     foreach (DataColumn dataColumn in dt.Columns) 
     { 
      xmlWriter.WriteElementString(dataColumn.ColumnName, dataRow[dataColumn].ToString()); 
     } 
     xmlWriter.WriteEndElement(); 
    } 
    xmlWriter.WriteEndElement();//</Work> 
    xmlWriter.WriteStartElement("Persons"); 
    foreach (DataRow dataRow in dt2.Rows) 
    { 
     xmlWriter.WriteStartElement("Person"); 
     foreach (DataColumn dataColumn in dt2.Columns) 
     { 
      xmlWriter.WriteElementString(dataColumn.ColumnName, dataRow[dataColumn].ToString()); 
     } 
     xmlWriter.WriteEndElement();//</Person> 
    } 
    xmlWriter.WriteEndElement();//</Persons> 
    xmlWriter.WriteEndElement();//</Address> 
} 

XML文件:

<Address> 
    <Work> 
    <Location> 
     <Location_ID>1</Location_ID> 
     <Location_NAME>Virginia</Location_NAME> 
    </Location> 
    </Work> 
    <Persons> 
    <Person> 
     <Person_ID>1</Person_ID> 
     <Person_Name>MARA</Person_Name> 
     <Location_ID>1</Location_ID> 
     <IsRequired>0</IsRequired> 
    </Person> 
    <Person> 
     <Person_ID>2</Person_ID> 
     <Person_Name>Tanner</Person_Name> 
     <Location_ID>1</Location_ID> 
     <IsRequired>0</IsRequired> 
    </Person> 
    <Person> 
     <Person_ID>3</Person_ID> 
     <Person_Name>Carlo</Person_Name> 
     <Location_ID>1</Location_ID> 
     <IsRequired>0</IsRequired> 
    </Person> 
    <Person> 
     <Person_ID>4</Person_ID> 
     <Person_Name>Casey</Person_Name> 
     <Location_ID>1</Location_ID> 
     <IsRequired>0</IsRequired> 
    </Person> 
    </Person> 
<Address> 

我的問題是我想爲person_id永遠是對人的計數文件。例如,當我在上面的XML中刪除Tanner的數據。該XML應該是這樣的

<Address> 
    <Work> 
    <Location> 
     <Location_ID>1</Location_ID> 
     <Location_NAME>Virginia</Location_NAME> 
    </Location> 
    </Work> 
    <Persons> 
    <Person> 
     <Person_ID>1</Person_ID> 
     <Person_Name>MARA</Person_Name> 
     <Location_ID>1</Location_ID> 
     <IsRequired>0</IsRequired> 
    </Person> 
    <Person> 
     <Person_ID>2</Person_ID> 
     <Person_Name>Carlo</Person_Name> 
     <Location_ID>1</Location_ID> 
     <IsRequired>0</IsRequired> 
    </Person> 
    <Person> 
     <Person_ID>3</Person_ID> 
     <Person_Name>Casey</Person_Name> 
     <Location_ID>1</Location_ID> 
     <IsRequired>0</IsRequired> 
    </Person> 
    </Person> 
<Address> 
+0

您是否嘗試過這麼遠嗎?如果是,請提供代碼。如果沒有,請嘗試一下並讓我們知道這些問題。 – Nitin

回答

2

嘗試XML LINQ

using System; 
using System.Collections.Generic; 
using System.Linq; 
using System.Text; 
using System.Xml; 
using System.Xml.Linq; 

namespace ConsoleApplication27 
{ 
    class Program 
    { 
     const string FILENAME = @"c:\temp\test.xml"; 
     static void Main(string[] args) 
     { 
      XDocument doc = XDocument.Load(FILENAME); 
      List<XElement> person_IDs = doc.Descendants("Person_ID").ToList(); 
      int count = 1; 
      foreach (XElement person_ID in person_IDs) 
      { 
       person_ID.Value = (count++).ToString(); 
      } 

     } 
    } 
} 
+0

這爲我工作。謝謝jdweng – user1998735