如何將字符串轉換爲帶分隔符的數組？

Question

我有以下列格式

myString = "cat+dog+cow" 

我需要存儲由+到一個陣列分離的每個字符串的字符串。 如：

myArray[0] = cat 
myArray[1] = dog 
myArray[2] = cow 

誰能告訴我正確的方式做到這一點？

Answer 1

componentsSeparatedByString:拆分字符串和數組返回結果。

NSArray *myArray = [myString componentsSeparatedByString:@"+"]; 

[myArray objectAtIndex:0];//cat 
[myArray objectAtIndex:1];//dog 
[myArray objectAtIndex:2];//cow 

Answer 2

試試這個..

NSArray *arr = [myString componentsSeparatedByString:@"-"]; 

[arr objectAtIndex:0];//Hai 
[arr objectAtIndex:1];//Welcome 

Answer 3

使用NSArray的componentsSeparatedByString:功能。

NSString string = @"hai-welcome"; 
NSArray myArray = [string componentsSeparatedByString:@"-"]; 

NSString* haiString = [myArray objectAtIndex:0]; 
NSString* welcomeString = [myArray objectAtIndex:1]; 

Answer 4

這是VERT簡單..

NSString * test = @"Hello-hi-splitting-for-test"; 
NSArray * stringArray = [test componentsSeparatedByString:@"-"]; 

// Now stringArray will contain all splitted strings.. :) 

希望這有助於...

你不想再使用陣列通過每個字符迭代我...

NSMutableString * splittedString = nil; 

for(int i=0;i<test.length;i++){ 

    unichar character = [test characterAtIndex:0]; 
    if (character=='-') { 

     if (splittedString!=nil) { 
      NSLog(@"String component %@",splittedString); 
      [splittedString release]; 
      splittedString = nil; 
     } 

    } else { 
     if (splittedString==nil) { 
      splittedString = [[NSMutableString alloc] init];     
     } 
     [splittedString appendFormat:@"%C",character]; 
    } 

} 

if (splittedString!=nil) { 
    NSLog(@"String last component %@",splittedString); 
    [splittedString release]; 
    splittedString = nil; 
} 

那就是所有...

Answer 5

NSArray *strArray = [myString componentsSeparatedByString:@"-"]; 

firstString = [strArray objectAtIndex:0];//Hai 
secondString = [strArray objectAtIndex:1];//Welcome 

Answer 6

NSArray *lines = [string componentsSeparatedByString:@"-"]; 

的第一個值將被存儲在的線和第二個值的第0索引將被存儲在的線 1號索引..

爲什麼不陣列？

Answer 7

這將是解決辦法，如果你正在處理一個字符串：

NSString *mySstring = @"hai-welcome"; 
NSMutableArray *anArray=[[NSMutableArray alloc] initWithArray:[componentsSeparatedByString: @"-"]]; 

而且每個字從0-N被存儲在相應的位置上。

試試這個。 :)

Answer 8

如果你不願意使用數組，可以考慮一下這款 -

NSString *accessMode, *message; 

NSScanner *scanner = [NSScanner scannerWithString:@"hai-welcome"]; 
NSCharacterSet *hyphenSet = [NSCharacterSet characterSetWithCharactersInString:@"-"]; 

[scanner scanUpToCharactersFromSet:hyphenSet intoString:&accessMode]; 
[scanner scanCharactersFromSet:hyphenSet intoString:nil]; 
[scanner scanUpToCharactersFromSet:[NSCharacterSet characterSetWithCharactersInString:@""] intoString:&message]; 

Answer 9

NSArray *myWords = [myString componentsSeparatedByString:@"+"]; 

Answer 10

你可以找到這個一個非常簡單的

NSString *str = @"cat+dog+cow"; 
NSArray *arr = [str componentsSeparatedByString:@"+"]; 
NSLog(@"Array items %@",arr); 

OUTPUT：

數組項 （ 貓，狗 ， 牛 ）

Answer 11

簡單代碼：

NSString *myString = [[NSString alloc] initWithString:@"cat+dog+cow"]; 
NSArray *resultArray = [tempString componentsSeparatedByString:@"+"]; 

NSLog(@"1. %@ 2. %@ 3. %@",[resultArray objectAtIndex:0],[resultArray objectAtIndex:1],[resultArray objectAtIndex:2]); 

Answer 12

試試這個：

NSString *str = @"cat+dog+cow" ; 
NSArray *array = [str componentsSeparatedByString:@"+"]; 
NSLog(@"%@",array) ;