需要幫助解析錯誤GNU Octave

Question

我嘗試在GNU Octave上編寫線性&非線性迴歸，作爲我的Numerical Method類的最終項目的一部分。不過，我的代碼中有一個錯誤，這是一個簡單的解析錯誤，但我不知道如何解決它。我嘗試修正語法或嘗試改變我的編碼方式仍然卡住。

printf("This program is use for curve fitting\n") 
printf("Please enter the data in the [] by use one space to seperate each element.\n") 
x = input("Enter the data(x group):") 
y = input("Enter the data(y group):") 
mode = input("What kind of fitting you want to do(expo((1),power(2),least-square fitting(3)):") 
switch mode 
case{3} 
    xbar = sum(x)/length(x) 
    ybar = sum(y)/length(y) 
    xy = x.*y 
    xs = x.^2 
    a1 = ((length(x)*sum(xy))-(sum(x)*sum(y)))/((sum(xs)*length(x))-(sum(x)^2)) 
    a0 = ybar-(a1*xbar) 
    disp(x) 
    disp(y) 
    printf("mean of x = %d,mean of y = %d,a1 = %d.a0 = %d",xbar,ybar,a1,a0) 
    plot(a0+(a1*x)) 
case{2} 
    xbar = sum(x)/length(x) 
    ybar = sum(y)/length(y) 
    xy = x.*y 
    xs = x.^2 
    a1 = ((length(x)*sum(xy))-(sum(x)*sum(y)))/((sum(xs)*length(x))-(sum(x)^2)) 
    a0 = ybar-(a1*xbar) 
    alpha = 10^a0 
    disp(x) 
    disp(y) 
    printf("mean of x = %d,mean of y = %d,a1 = %d.a0 = %d,alpha = %d,beta = %d\n",xbar,ybar,a1,a0,alpha,a0) 
    plot((alpha.*(x^a1)) 
case{1} 
    xbar = sum(x)/length(x) 
    ybar = sum(y)/length(y) 
    xy= x.*y 
    xs= x.^2 
    a1 = ((length(x)*sum(xy))-(sum(x)*sum(y)))/((sum(xs)*length(x))-(sum(x)^2)) 
    a0 = ybar-(a1*xbar) 
    disp(x) 
    disp(y) 
    alpha = e^a1 
    printf("mean of x = %d,mean of y = %d,a1 = %d.a0 = %d,alpha = %d,beta = %d\n",xbar,ybar,a1,a0,alpha,a0) 
    plot(a0*(e^((a1*alpha).*x)) 
otherwise 
    break; 
end 

解析錯誤一直告訴發生錯誤的地方是{1}，但我不知道錯誤是什麼。

Answer 1

這種情況下，標籤的前行不匹配的括號：

plot((alpha.*(x^a1))