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我正在研究一個允許用戶對食譜評分的項目。我做了一個簡單的連接表(RecipeRating),用戶和配方都共享,但ActiveRecord無法保存。ActiveRecord無法保存記錄:「零長度分隔標識符」
@rating = @user.recipe_ratings.where(:recipe_id => @recipe.id).first
@rating.rating = params[:rating]
@rating.save
產量:
ActiveRecord::StatementInvalid in UsersController#rate_recipe
PG::Error: ERROR: zero-length delimited identifier at or near """"
LINE 1: ...013-08-07 14:28:39.965953' WHERE "recipe_ratings"."" IS NULL
^
: UPDATE "recipe_ratings" SET "rating" = 3, "updated_at" = '2013-08-07 14:28:39.965953' WHERE "recipe_ratings"."" IS NULL
顯然,錯誤是由WHERE "recipe_ratings"."" IS NULL
引起的,但什麼原因造成這一點,我該如何解決?作爲參考,它創建或找到評級沒有問題(在我的數據庫中按預期保存),它只是無法更新它們。
參考:
class User < ActiveRecord::Base
...
has_many :recipe_ratings
end
class Recipe < ActiveRecord::Base
...
has_many :recipe_ratings
end
class RecipeRating < ActiveRecord::Base
belongs_to :recipe
belongs_to :user
attr_accessible :comment, :rating, :user, :recipe#, :user_id, :recipe_id
end
試試這個,以防萬一:'@rating = @ user.recipe_ratings.find_by_recipe_id(@ recipe.id)' – Raindal