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我正在使用php代理從另一個我的網站解析表單。它工作正常,但提交按鈕url的表單動作和img src是相對的。我怎樣才能在表單中每個url的前面加上完整的http // www.domain.com /?用jQuery更改操作和圖像src url
編輯:
這裏的一次通過輸送到新域的表單代碼:
<div style="display: none;" id="SubscribeForm" class="newform">
<h5>Subscribe to our newsletter</h5>
<form action="/CampaignProcess.aspx?ListID=27057" method="post" onsubmit="return checkWholeForm93426(this)" name="catemaillistform93426">
<div class="form">
<div class="item">
<label for="CLFullName">Full Name</label>
<br />
<input type="text" maxlength="255" id="CLFullName" name="FullName" class="cat_textbox_small" style="background-color: #ffffa0;" />
</div>
<div class="item">
<label for="CLEmailAddress">Email Address</label>
<br />
<input type="text" maxlength="255" id="CLEmailAddress" name="EmailAddress" class="cat_textbox_small" style="background-color: #ffffa0;" />
</div>
<div class="item">
<label>Enter Word Verification in box below</label>
<br />
<div class="captchaimg"><img src="/captchahandler.ashx?ID=22791bf65054422cadeb4aea9390cfaa&Color=DimGray&ForeColor=White&Width=160" alt="Captcha Image" /></div>
<input id="CaptchaV2" class="cat_textbox" type="text" name="CaptchaV2" style="width:160px" />
<input id="CaptchaTV2" type="text" name="CaptchaTV2" style="display:none;" />
<input id="CaptchaHV2" type="hidden" value="22791bf65054422cadeb4aea9390cfaa" name="CaptchaHV2" />
</div>
<div class="item">
<p>We respect your privacy and will never share your details.</p>
</div>
<div class="item">
<input type="image" src="/images/submit-button-white-bg_07.gif" id="catlistbutton" value="Subscribe" class="cat_button" />
</div>
</div>
<script type="text/javascript" src="http://testsite.businesscatalyst.com/CatalystScripts/ValidationFunctions.js"></script>
<script type="text/javascript">function checkWholeForm50598(theForm){var why = "";if (theForm.EmailAddress) why += checkEmail(theForm.EmailAddress.value);if (theForm.CaptchaV2) why += isEmpty(theForm.CaptchaV2.value, "Enter Word Verification in box below"); if (why != ""){alert(why);return false;}theForm.submit();return false;}</script>
</form>
</div>
,這裏是我使用的嘗試和改變操作URL jQuery的:
jQuery(document).ready(function($) {
$('form').each(function(index) {
var urls = $(this).attr('action');
var dom = 'http://www.sampleurl.com';
$(this).attr('action',dom+urls);
});
});
所有其他jQuery函數在頁面上運行良好,所以我知道這不是jQuery本身的問題。
如果它真的是你的**網站 - 獲取**你的**源並將它們放到另一個項目中,而不需要任何解析。 – zerkms 2010-12-02 06:07:50
「解析來自我的另一個站點的表單」是什麼意思?你能詳細說明嗎? – Lee 2010-12-02 06:08:05