2015-06-16 61 views
0

這裏有一些上下文信息:我正在用Doctrine2和FOSRestBundle構建一個Symfony2應用程序。Doctrine2級聯創建

我的問題:我想能夠創建一個家長與他的孩子只有一個JSON和一個數據庫訪問。

我的JSON是這樣的:

{ 
    "name": "TEST_NAME", 
    "info": "TEST_INFO", 
    "cmts": [ 
     { 
      "cmt": "CMT1", 
      "info": "INFO1" 
     }, 
     { 
      "cmt": "CMT2", 
      "info": "INFO2" 
     }, 
     { 
      "cmt": "CMT3", 
      "info": "INFO3" 
     } 
    ] 
} 

這裏是我的測試實體:

<?php 

namespace App\Bundle\DemoBundle\Entity; 

use Doctrine\ORM\Mapping as ORM; 
use Doctrine\Common\Collections\ArrayCollection; 
use Symfony\Component\Validator\Constraints as Assert; 

/** 
* Test 
* 
* @ORM\Table(name="Test") 
* @ORM\Entity(repositoryClass="App\Bundle\DemoBundle\Entity\TestRepository") 
*/ 
class Test 
{ 
    /** 
    * @var integer 
    * 
    * @ORM\Column(name="id", type="integer") 
    * @ORM\Id 
    * @ORM\GeneratedValue(strategy="AUTO") 
    */ 
    private $id; 

    /** 
    * @var string 
    * 
    * @ORM\Column(name="name", type="string", length=255) 
    * @Assert\NotBlank() 
    */ 
    private $name; 

    /** 
    * @var string 
    * 
    * @ORM\Column(name="info", type="string", length=255, nullable=true) 
    */ 
    private $info; 

    /** 
    * @ORM\OneToMany(targetEntity="TestCmt", mappedBy="test", fetch="EAGER", orphanRemoval=true, cascade={"merge", "remove", "persist"}) 
    */ 
    protected $cmts; 

    /** 
    * Constructor 
    */ 
    public function __construct() 
    { 
     $this->cmts = new \Doctrine\Common\Collections\ArrayCollection(); 
    } 

    /** 
    * Add cmts 
    * 
    * @param \App\Bundle\DemoBundle\Entity\TestCmt $cmts 
    * @return Test 
    */ 
    public function addCmt(\App\Bundle\DemoBundle\Entity\TestCmt $cmts) 
    { 
     $this->cmts[] = $cmts; 

     return $this; 
    } 

    /** 
    * Remove cmts 
    * 
    * @param \App\Bundle\DemoBundle\Entity\TestCmt $cmts 
    */ 
    public function removeCmt(\App\Bundle\DemoBundle\Entity\TestCmt $cmts) 
    { 
     $this->cmts->removeElement($cmts); 
    } 

    /** 
    * Get cmts 
    * 
    * @return \Doctrine\Common\Collections\Collection 
    */ 
    public function getCmts() 
    { 
     return $this->cmts; 
    } 

    // other getters/setters... 
} 

而且我TESTCMT實體:

<?php 

namespace App\Bundle\DemoBundle\Entity; 

use Doctrine\ORM\Mapping as ORM; 

/** 
* TestCmt 
* 
* @ORM\Table(name="TestCmt") 
* @ORM\Entity(repositoryClass="App\Bundle\DemoBundle\Entity\TestCmtRepository") 
*/ 
class TestCmt 
{ 
    /** 
    * @var integer 
    * 
    * @ORM\Column(name="id", type="integer") 
    * @ORM\Id 
    * @ORM\GeneratedValue(strategy="AUTO") 
    */ 
    private $id; 

    /** 
    * @var string 
    * 
    * @ORM\Column(name="cmt", type="string", length=255) 
    */ 
    private $cmt; 

    /** 
    * @var string 
    * 
    * @ORM\Column(name="info", type="string", length=255, nullable=true) 
    */ 
    private $info; 

    /** 
    * @var Test 
    * 
    * @ORM\ManyToOne(targetEntity="Test", inversedBy="cmts") 
    * @ORM\JoinColumn(name="test_id", referencedColumnName="id") 
    **/ 
    private $test;  

    /** 
    * Set test 
    * 
    * @param \App\Bundle\DemoBundle\Entity\Test $test 
    * @return TestCmt 
    */ 
    public function setTest(\App\Bundle\DemoBundle\Entity\Test $test = null) 
    { 
     $this->test = $test; 

     return $this; 
    } 

    /** 
    * Get test 
    * 
    * @return \App\Bundle\DemoBundle\Entity\Test 
    */ 
    public function getTest() 
    { 
     return $this->test; 
    } 
} 

而且finaly我postTestAction():

public function postTestAction(Request $request) 
{ 
    $entity = $this->deserialize($request, 'App\DemoBundle\Entity\Test'); 

    $em = $this->getDoctrine()->getManager(); 
    $em->persist($entity); 
    $em->flush(); 

    return $entity; 
} 

當我發送JSON時,會創建TEST和TESTCMTs。儘管如此,創建的TESTCMT中的所有「test_id」都是「null」...這就是我的問題!

編輯:使用SQL Server事件探查器,我可以看到,教義做出處理SQL請求:

INSERT INTO TESTCMT (test_id, cmt, info) VALUES (null, 'CMT', 'INFO') 

我不知道爲什麼學說不能發送爲test_id ...... TEST被TESTCMT之前創建,因此Doctrine可以訪問「test_id」來創建關聯的TESTCMT。

有人可以幫我解決嗎? :)

+0

一個新的ID,請,我真的需要知道如何給全自動FK到兒童與級聯= {「堅持」,「合併」}! –

回答

0

刪除@ORM \ GeneratedValue(策略=「AUTO」),它不會讓數據庫生成實體

+0

我無法嘗試,因爲我不再在這個項目上工作。但謝謝你的答案! –