PHP的mail（）函數使用不工作的PHPMailer

Question

<?php 

require 'PHPMailerAutoload.php'; 
//echo !extension_loaded('openssl')?"Not Available":"Available <br/>"; 

$name = $_POST['username']; 
$email = $_POST['email']; 
$number = $_POST['phone']; 
$profession = $_POST['profession']; 

$to = 'example@gmail.com'; 
$subject = 'user registration'; 
$phone = "phone number:".$number; 

$message = "client details:"."\n"."Name:".$name."\n"."email:".$email."\n"."phone number:".$number."\n"."profession:".$profession; 

$headers = "From:".$email; 

$mail = new PHPMailer; 

//$mail->SMTPDebug = 3;        

$mail->isSMTP();          
$mail->Host = 'ssl://smtp.gmail.com';  
$mail->SMTPAuth = true;        
$mail->Username = 'example@gmail.com';      
$mail->Password = 'password';       
$mail->SMTPSecure = 'ssl'; 
$mail->Port = 465; 

$mail->setFrom($email, $name); 

$mail->Subject = $subject; 
$mail->Body = $message; 

if($mail->send()) { 
    header("Location: ../../thankyouNew.html"); 
} 
else { 
    header("Location: ../../somethingWrong.html"); 
} 

？>

代碼執行else塊，我想將郵件發送到example@gmail.com和郵件後返回用戶的thankyou.html頁函數執行。我是新的這個PHP和我非常感謝幫助提前謝謝你。 忘記下面的行........

Answer 1

你實際上並沒有指定你想發送郵件的地方。您需要使用addAddress()方法，如下所示。此方法需要一個參數，但您可以提供兩個 - 與您的方法具有相同的方式;首先是目標地址，然後是可選的顯示名稱。

$mail = new PHPMailer; 

// ... 

$mail->setFrom($email, $name); 
$mail->addAddress($to); // Add this method to specify a recipient 
$mail->Subject = $subject; 
$mail->Body = $message; 
if($mail->send()) { 
    // ... 
} 
// ...