無法使用django保存模型實例

我正在嘗試保存基於按鈕提交的簡單數據。但我不斷收到以下錯誤：無法使用django保存模型實例

TypeError at /exercise/1/ 
save() got an unexpected keyword argument 'commit'

models.py：

class StrategyHistory(models.Model): 
    user = models.ForeignKey(User) 
    strategy = models.ForeignKey(Strategies) 

    created = models.DateTimeField(editable=False) 
    modified = models.DateTimeField() 

    def save(self, *args, **kwargs): 
     ''' On save, update timestamps ''' 
     if not self.id: 
      self.created = datetime.datetime.today() 
     self.modified = datetime.datetime.today() 
     return super(StrategyHistory, self).save(*args, **kwargs) 

    def __unicode__(self): 
     return self.strategy.name

views.py：

def exercise_view(request, pk): 
    template_name = 'mobileApp/page/exercise.html' 
    if not request.user.is_authenticated(): 
     return HttpResponseRedirect(reverse('mobile_user_login')) 

    strategy = Strategies.objects.get(pk=pk) 

    context = { 
     'strategy':strategy, 
    } 

    if request.method == 'POST': 
     strategyhistory = StrategyHistory() 
     entry = strategyhistory.save(commit=False) 
     entry.user = self.request.user 
     entry.strategy = Strategies.objects.get(id=pk) 
     entry.save() 
     if pk < 5: 
      return HttpResponseRedirect(reverse('mobile_exercise', kwargs={'pk':pk+1})) 
     else: 
      return HttpResponseRedirect(reverse('mobile_comeback_later')) 

    return render_to_response(template_name, 
    context, 
    context_instance = RC(request, {}))

HTML文件：

 <form action="" method="post">{% csrf_token %} 
      <a href="#" data-role="button" data-inline="true" data-rel="back" data-transition="flow" data-icon="refresh" data-theme="c">Prøv igen</a> 
      <button type="submit" value="submit" data-inline="true" data-transition="flow" data-icon="check" data-theme="b">Fortsæt</button> 
     </form>

我運行Django 1.6.2

來源

2014-04-02 JavaCake

用於創建和更新時間，我有這個在我的項目：CREATION_TIME = models.DateTimeField（auto_now_add =真，auto_now = FALSE） UPDATE_TIME =模型.DateTimeField（auto_now_add = False，auto_now = True） –

您不必同時指定'auto_now'這個動作。 –

您的看法使用StrategyHistory模型不正確。這是表單的使用。這是對的。

def exercise_view(request, pk): 
    template_name = 'mobileApp/page/exercise.html' 
    if not request.user.is_authenticated(): 
     return HttpResponseRedirect(reverse('mobile_user_login')) 

    strategy = Strategies.objects.get(pk=pk) 

    context = { 
     'strategy':strategy, 
    } 

    if request.method == 'POST': 
     strategyhistory = StrategyHistory.objects.create(
      user=request.user, 
      strategy=strategy) 
     if pk < 5: 
      return HttpResponseRedirect(reverse('mobile_exercise', kwargs={'pk': pk + 1})) 
     else: 
      return HttpResponseRedirect(reverse('mobile_comeback_later')) 

    return render_to_response(template_name, 
           context, 
           context_instance = RC(request, {}))

此外，您不能在該視圖中使用self.request。沒有自我聲明。

來源

2014-04-02 13:27:31

可能這是你想要什麼：

class StrategyHistory(models.Model): 
    user = models.ForeignKey(User) 
    strategy = models.ForeignKey(Strategies) 

    created = models.DateTimeField(auto_now_add=True) 
    modified = models.DateTimeField(auto_now=True) 


    def __unicode__(self): 
     return self.strategy.name

來源

2014-04-02 13:39:46 shellbye

無法使用django保存模型實例

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