-2
任何人都可以幫助解決此錯誤嗎?我想在我的系統中登錄會話。這是編碼。警告:mysql_num_rows()期望參數1是資源,在第27行C: wamp www novel loginadmin.php中給出的布爾值
<?PHP
error_reporting (E_ALL^E_NOTICE);
session_start();
$username =$_POST['username'];
$password =$_POST['password'];
if ($username && $password)
{ // if 1
$server='localhost';
$userid2='root';
$password2='';
$dbname='suhaibah';
$conn=mysql_connect("$server", "$userid2", "$password2");
mysql_select_db("$dbname", $conn) or die(mysql_error());
$query = mysql_query("select * from staff where username = '$username'");
$numrows = mysql_num_rows($query);
if ($numrows !=0)
{ // if 2
while ($row = mysql_fetch_assoc($query))
{ // if 3
$dbusername = $row['username'];
$dbpassword = $row['password'];
} // if 3
if ($username==$dbusername&&$password==$dbpassword)
{
//echo "You're in! <a href='index2.php'>click </a> here to enter";
$_SESSION['username']=$username;
header('Location: http://localhost/novel/lamanutamaadmin.php') ;
}
else
{echo " Incorrect Password!! <a href='/novel/landingpageadmin.php'>Click here to login</a>";}
} // if 2
else
die (" That user dosen't exist<a href='/novel/landingpageadmin.php'>Click here to login</a>");
} // if 1
else
{
echo "Please enter userid and password!!<a href='/novel/landingpageadmin.php'>Click here to login</a>";
}
?>
</body>
</html>
請參閱[本答案](http://stackoverflow.com/a/11674313/250259)瞭解如何解決此問題。 –
您對「//評論」的使用乍一看實在令人困惑。我想知道你爲什麼要放'if 1' – Sir