你好我想完成我的家庭作業。當我嘗試分離課程時出現編譯錯誤,然後再調用它。但整個測試功能正常工作。它在整個文本中都有類。基本上,當我嘗試從文本中分離類時,我有一條錯誤消息。類的頭,串沒有指定類型
#include <iostream>
#include<string>
using namespace std;
class Person
{
private:
string alpha;
int beta;
public:
Person(string Name, int Age)
{
alpha = Name;
beta = Age;
}
string getName()
{
return alpha;
}
int getAge()
{
if (beta < 0)
{ beta = 0;
cout << "Error. A negative age cannot be entered. " << endl;
}
if (beta > 120)
{
cout << "Damn you're old. How many heart transplants have you had? You Vampire " << endl;
}
return beta;
}
void setName(string alpha)
{
}
void setAge(int beta);
void display();
};
int main()
{
Person Lu("Jess ", 22);
Person Rose("Gary ", 49);
cout << Lu.getAge() << " " << Lu.getName() <<endl;
cout << Rose.getAge() << " " << Rose.getName() << endl;
return 0;
}`
但是,當我分開類,:
#include <iostream>
#include <string>
class Person
{
private:
string alpha;
int beta;
public:
Person(string Name, int Age)
{
alpha = Name;
beta = Age;
}
string getName()
{
return alpha;
}
int getAge()
{
if (beta < 0)
{ beta = 0;
cout << "Error. A negative age cannot be entered. " << endl;
}
if (beta > 120)
{
cout << "Damn you're old. How many heart transplants have you had? You Vampire " << endl;
}
return beta;
}
void setName(string alpha)
{
}
void setAge(int beta);
void display();
};
主文件
#include <iostream>
#include "Person.h"
#include <string>
using namespace std;
int main()
{
Person Lu("Jess ", 22);
cout << Lu.getAge() << " " << Lu.getName() <<endl;
return 0;
}`
但是,當我分開類,我得到的代碼塊的錯誤。請幫忙。
有什麼錯誤訊息? – approxiblue
第7行錯誤:「串」沒有指定類型 –
您應編輯爲你的問題。 – approxiblue