帶動作的Powershell方法<T>參數

-1

如何執行一個將Action<T>作爲Powershell中的參數的方法？帶動作的Powershell方法<T>參數

upgradeEngine.Configure(c => c.ScriptExecutor.ExecutionTimeoutSeconds = 15 * 60);

C＃代碼：

var upgradeEngine = DeployChanges.To 
    .SqlDatabase(connectionString) 
    .WithScriptsEmbeddedInAssembly(Assembly.GetExecutingAssembly()) 
    .LogToConsole(); 

//this line 
upgradeEngine.Configure(c => c.ScriptExecutor.ExecutionTimeoutSeconds = 15 * 60); 

//this line 
upgradeEngine.Build();

Add-Type -Path (Join-Path -Path $currentPath -ChildPath 'x:\location\of\DbUp.dll') 

$dbUp = [DbUp.DeployChanges]::To 
$dbUp = [SqlServerExtensions]::SqlDatabase($dbUp, $connectionString) 
$dbUp = [StandardExtensions]::WithScriptsFromFileSystem($dbUp, $scriptPath) 
$dbUp = [StandardExtensions]::LogToConsole($dbUp) 
$upgradeResult = $dbUp.Build().PerformUpgrade()

來源

2017-04-16 Vadim K

GSerg，沒有參數的使用從這個方法 –

我不確定你的意思，但委託接受一個參數'$ i'並使用它。 – GSerg

構建腳本塊與適當的簽名和將它轉換爲[Action[T]]

$delegate = [System.Action[DbUp.Builder.UpgradeConfiguration]]{ 
    param([DbUp.Builder.UpgradeConfiguration]$c) 
    $c.ScriptExecutor.ExecutionTimeoutSeconds = 15 * 60 
} 
$DbUp.Configure($delegate)

來源

2017-04-16 12:14:51

帶動作的Powershell方法<T>參數

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