當我收到一封電子郵件時,我只想將此電子郵件的一部分保存在數據庫中,因此,我使用正則表達式來刪除不需要的部分。但是,這不起作用。PHP preg_replace在沒有硬編碼的情況下無法工作
function emailToMessage($inbox, $emails){
$messages = [];
foreach ($emails as $email_number){
# $overview contient les infos du mail
$overview = imap_fetch_overview($inbox,$email_number,0);
$headerInfos = imap_headerinfo($inbox,$email_number);
$mailHeader = imap_fetchheader($inbox,$email_number);
$structure = imap_fetchstructure($inbox,$email_number);
$subject = (isset($overview[0]->subject)) ?$overview[0]->subject : 'Pas de sujet';
$sender = $headerInfos->from[0]->mailbox . "@" . $headerInfos->from[0]->host;
$body = imap_fetchbody($inbox,$email_number,1);
$body = checkSubtype($structure, $body); // decode if the transfert encoding is base64 and change encoding to utf8
$text = cleanMail($body, $mailHeader);
#conversion de udate en format pouvant etre inséré dans mySql
$mailDateAndTime = date("Y-m-d H:i:s", $overview[0]->udate);
$message = [
'title' => $subject,
'text' => $text,
'id_sender' => $sender,
'mailDateAndTime' => $mailDateAndTime,
];
$messages[] = $message;
}
return $messages;
}
function cleanMail($text, $mailHeader){
$clientMail = checkMailClient($mailHeader);
switch($clientMail){
case "gmail":
echo($text . "<br>");
$gmail = preg_replace("/\s+[0-9]{4}-[0-9]{2}-[0-9]{2}\s+[0-9]{2}:[0-9]{2}\s+GMT\+[0-9]{2}:[0-9]{2}\s+(.)*\s+:(?:\s(.)*)*/i", '$1', $text);
echo($gmail . "<br>");
return $gmail;
break;
如果
$body = "test
2017-09-11 11:55 GMT+02:00 XXX :
> frgthyjuki";
回波($文本);和echo($ gmail);既給我:
測試
2017年9月11日11:55 GMT + 02:00 XXX:
> frgthyjuki
但是,如果我申報$文本emailToMessage()(在$ body = checkSubtype($ structure,$ body);和$ text = cleanMail($ body,$ mailHeader);)或cleanMail()這行之間起作用。
switch($clientMail){
$text = "test
2017-09-11 11:55 GMT+02:00 XXX :
> frgthyjuki";
case "gmail":
echo($text . "<br>");
$gmail = preg_replace("/\s+[0-9]{4}-[0-9]{2}-[0-9]{2}\s+[0-9]{2}:[0-9]{2}\s+GMT\+[0-9]{2}:[0-9]{2}\s+(.)*\s+:(?:\s(.)*)*/i", '$1', $text);
echo($gmail . "<br>");
return $gmail;
break;
echo($ text);會給
測試
2017年9月11日11:55 GMT + 02:00 XXX:
> frgthyjuki
和回波($ GMAIL);將給:
測試
爲什麼當變量是硬編碼是隻工作?我能做些什麼來解決它?
UPDATE
function checkSubtype($structure, $body){
$subtype = strtolower($structure->subtype);
if($subtype == "alternative") {
$encoding = $structure->parts[0]->parameters[0]->value;
$encoding = strtolower($encoding);
$transferEncoding = $structure->parts[0]->encoding;
$body = checkIfBase64($body, $transferEncoding);
$body = quoted_printable_decode($body);
$body = changeToUTF8($body, $encoding);
} else {
$transferEncoding = $structure->encoding;
$body = checkIfBase64($body, $transferEncoding);
}
return $body;
}
-
function checkIfBase64($text, $transferEncoding){
if($transferEncoding == "3"){
$text = base64_decode($text);
}
return $text;
}
function changeToUTF8($text, $encoding){
if($encoding != "utf-8" && $encoding != 'utf8'){
$text = utf8_encode($text);
}
return $text;
}
UPDATE 2
我雷鳥和橙測試。
我沒有與Thunderbird一起工作(我在網上查了RegEx,這是正確的),但它適用於Orange。
case "orange":
return preg_replace("/s*>(?:\s(?:.)*)*/i", '$1', $text);
break;
我真的不明白...
更新3
我重新嘗試不可怕的解決方案,它與以前的代碼工作。 這很奇怪...
檢查base64事件是否返回您的字符串。 – delboy1978uk