Question

你好，我有點麻煩讓這段代碼工作。

<?php 
$filename = "test.php"; 
$filehandle = fopen($filename, 'a') or die("can't open file"); 
$test= 
    ' 
     $conn = mysql_connect("server", "username", "password") or die (mysql_error()) ; 
     mysql_select_db("db", $conn); 
     $query = "select * from test"; 
     $result = mysql_query ($query); 
     $row = mysql_fetch_array($result); 

     echo $row[\'test\']; 

    '; 
fwrite($filehandle, $test); 
fclose($filehandle); 
?> 

，而不是輸出它輸出的查詢，而不是查詢的結果，我想這是因爲我存儲在一個變量的完整的查詢，沒有人知道如何我將能夠輸出的結果查詢而不是實際的查詢？感謝您的幫助。

Answer 1

您應該使用庫MySQLi或PDO

但是你的代碼應該是這個樣子：

$filename = "test.php"; 
$filehandle = fopen($filename ,'a') or die("can't open file"); 
$conn = mysql_connect("server" ,"username" ,"password") or die (mysql_error()) ; 
mysql_select_db("db" ,$conn); 
$query = "select * from test"; 
$result = mysql_query($query); 
// Iterate through results 
while($row = mysql_fetch_array($result)) 
{ 
// var_dump[$row]; 
    // Replace your-column-name below with the actual name : 
    fwrite($filehandle ,$row['your-column-name']); 
} 
fclose($filehandle); 

Fi nd手冊頁的一些示例：mysql_fetch_array,mysql_fetch_assoc,mysql_fetch_array。

Answer 2

你不覺得它應該是這樣的：

<?php 
$conn = mysql_connect("server", "username", "password") or die (mysql_error()) ; 
mysql_select_db("db", $conn); 
$query = "select * from test"; 
$result = mysql_query ($query); 
$row = mysql_fetch_array($result); 
$test = $row['test']; 
$filename = "test.php"; 
$filehandle = fopen($filename, 'a') or die("can't open file"); 
fwrite($filehandle, $test); 
fclose($filehandle); 
?> 

Answer 3

<?php 
$filename = "test.php"; 
$filehandle = fopen($filename, 'a') or die("can't open file"); 

// do the query 
$conn = mysql_connect("server", "username", "password") or die (mysql_error()) ; 
mysql_select_db("db", $conn); 
$query = "select * from test"; 
$result = mysql_query ($query); 

// get the result row 
$row = mysql_fetch_array($result); 

// write a field to file 
fwrite($filehandle, $row['test']); 
fclose($filehandle); 
?>