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我有了這個樸素簡單的配置文件:爲什麼我不能導入Mule配置文件?
<?xml version="1.0" encoding="UTF-8"?>
<mule xmlns:jdbc-ee="http://www.mulesoft.org/schema/mule/ee/jdbc" xmlns="http://www.mulesoft.org/schema/mule/core" xmlns:http="http://www.mulesoft.org/schema/mule/http" xmlns:jersey="http://www.mulesoft.org/schema/mule/jersey" xmlns:doc="http://www.mulesoft.org/schema/mule/documentation" xmlns:spring="http://www.springframework.org/schema/beans" xmlns:core="http://www.mulesoft.org/schema/mule/core" xmlns:cxf="http://www.mulesoft.org/schema/mule/cxf" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:vm="http://www.mulesoft.org/schema/mule/vm" xmlns:jdbc="http://www.mulesoft.org/schema/mule/jdbc" xmlns:jms="http://www.mulesoft.org/schema/mule/jms" xmlns:test="http://www.mulesoft.org/schema/mule/test" version="EE-3.4.1" xsi:schemaLocation="http://www.mulesoft.org/schema/mule/http http://www.mulesoft.org/schema/mule/http/current/mule-http.xsd
http://www.mulesoft.org/schema/mule/jersey http://www.mulesoft.org/schema/mule/jersey/current/mule-jersey.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.mulesoft.org/schema/mule/core http://www.mulesoft.org/schema/mule/core/current/mule.xsd
http://www.mulesoft.org/schema/mule/cxf http://www.mulesoft.org/schema/mule/cxf/current/mule-cxf.xsd
http://www.mulesoft.org/schema/mule/vm http://www.mulesoft.org/schema/mule/vm/3.2/mule-vm.xsd
http://www.mulesoft.org/schema/mule/ee/jdbc http://www.mulesoft.org/schema/mule/ee/jdbc/current/mule-jdbc-ee.xsd
http://www.mulesoft.org/schema/mule/jms http://www.mulesoft.org/schema/mule/jms/3.2/mule-jms.xsd
http://www.mulesoft.org/schema/mule/test http://www.mulesoft.org/schema/mule/test/3.2/mule-test.xsd">
<spring:import resource="dataSources.xml"/>
<jdbc-ee:connector name="apiJDBCConnector" dataSource-ref="apiLogDataSource">
<jdbc-ee:query key="commitAPILogEntries" value="insert into APILogEntries
(requestName, parameters, serviceParameters, partnerID, partnerIP, statusCode, responseLength, time)
values
(#[map-payload:REQUEST_NAME], #[map-payload:PARAMETERS], #[map-payload:SERVICE_PARAMETERS], #[map-payload:PARTNER_ID]::int, inet(#[map-payload:PARTNER_IP]), #[map-payload:STATUS_CODE]::int, #[map-payload:RESPONSE_LENGTH]::int, TIMESTAMP WITHOUT TIME ZONE 'epoch' + #[map-payload:TIMESTAMP]::bigint * INTERVAL '1 millisecond')"></jdbc-ee:query>
</jdbc-ee:connector>
</mule>
我想要做的,是在一個單獨的配置文件來定義數據源,然後在其他地方使用這些數據源。不過,我把數據源-ref元素上得到錯誤和Mule拒絕運行。
的dataSources.xml文件看起來是這樣的:
<?xml version="1.0" encoding="UTF-8"?>
<spring:beans>
<spring:bean id="apiLogDataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
<spring:property name="driverClassName" value="${jdbc.driverClassName}"/>
<spring:property name="url" value="${jdbc.apilog.url}"/>
<spring:property name="username" value="${jdbc.apilog.username}"/>
<spring:property name="password" value="${jdbc.apilog.password}"/>
</spring:bean>
</spring:beans>
我在做什麼錯了,因爲我不能得到這個工作?