單引號裏面雙引號php

Question

我正在更新我使用硬編碼日期從使用常量從配置文件中使用的腳本。這是工作好，直到我得到了以下一點。

原：

function getDestroyedRelationships($relation){ 
$owner_user_id = $_REQUEST['owner_user_id']; 
$tableName = ""; 
if($relation=="friends"){ 
    $tableName = "yst_twitter_following_relationships"; 
}else if($relation=="followers"){ 
    $tableName = "yst_twitter_follower_relationships"; 
}else{ 
    return false; 
} 
$twitters = NULL; 
$stmt = ulPdoDb::Prepare('log', 'SELECT your_id FROM '.$tableName.' WHERE my_id=? AND updated_on<(SELECT MAX(updated_on) FROM '.$tableName.' WHERE my_id=?)'); 
if (!ulPdoDb::BindExec(
    $stmt, 
    array(  // output 
     &$twitters, 'lob' 
    ), 
    array(  // input 
     &$owner_user_id, 'int', 
     &$owner_user_id, 'int' 
    ) 
)) 
{ 
    ul_db_fail(); 
    return false; 
} 

if ($twitters = $stmt->fetchAll(PDO::FETCH_COLUMN)) 
{ 
    return $twitters; 
} 
else 
{ 
    //echo "Nothing"; 
} 
return $twitters; 
} 

正如你可以在上面看到的$表名具有表前綴「YST」定義。我想改變「YST」閱讀：執行此操作時

'.TABLE_PREFIX' 

不過，我得到以下錯誤：

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''.TABLE_PREFIX.'_twitter_following_relationships (my_id, your_id, created_on, up' 

我懷疑這是用單引號是旁邊做雙引號？

有什麼建議嗎？ 感謝

Answer 1

假設TABLE_PREFIX是你在什麼地方定義的常量，只是這樣做：

$tableName = TABLE_PREFIX.'_twitter_following_relationships';