如何在shell腳本中編寫用戶定義的選項？

Question

可能重複：
Using getopts in bash shell script to get long and short command line options

這是我寫

#! /bin/bash 

getopts master $1 

while getopts ":master" opt; do 
    case $opt in 
    master) 
     echo "-master was triggered! $1 was entered" >&2 
     ;; 
    \?) 
     echo "Invalid option: -$OPTARG" >&2 
     ;; 
    esac 
done 

的代碼，這是輸出我是getting-

]$ ./test123.sh -master 123 
./test123.sh: line 3: getopts: `-master': not a valid identifier 

我如何定義用戶定義的選項？

Answer 1

我認爲有幾個問題。

1. 我不明白這是什麼（getopts master $1）在做什麼，你可以刪除它
2. 我想你需要單個字符參數（即-m VS -master）

例如下面似乎工作：

#!/bin/bash 
while getopts ":m" opt; do 
    case $opt in 
    m) 
     echo "-m was triggered! $1 was entered" >&2 
     ;; 
    \?) 
     echo "Invalid option: -$OPTARG" >&2 
     ;; 
    esac 
done