獲取所有的獨特變化

下面是I類有：獲取所有的獨特變化

public class Schedule 
{ 
    public string mintime { get; set; } 
    public string maxtime { get; set; } 
    public string weekday { get; set; } 
}

我有這樣的任務，而且重複工作日列表像

List<Schedule> list = new List<Schedule> { 
    new Schedule { mintime = "01.01.2012", maxtime = "05.01.2012", weekday = "1" }, 
    new Schedule { mintime = "05.01.2012", maxtime = "10.01.2012", weekday = "1" }, 
    new Schedule { mintime = "10.01.2012", maxtime = "20.01.2012", weekday = "2" }, 
    new Schedule { mintime = "01.02.2012", maxtime = "10.02.2012", weekday = "2" }, 
    new Schedule { mintime = "01.03.2012", maxtime = "10.03.2012", weekday = "3" }, 
    new Schedule { mintime = "01.04.2012", maxtime = "10.04.2012", weekday = "4" } 
};

我怎樣才能名單>中包含的所有組合：

List<List<Schedule>> list = new List<List<Schedule>> { 
    new List<Schedule> { 
     new Schedule { mintime = "01.01.2012", maxtime = "05.01.2012", weekday = "1" }, 
     new Schedule { mintime = "10.01.2012", maxtime = "20.01.2012", weekday = "2" }, 
     new Schedule { mintime = "01.03.2012", maxtime = "10.03.2012", weekday = "3" }, 
     new Schedule { mintime = "01.04.2012", maxtime = "10.04.2012", weekday = "4" } 
    }, 
    new List<Schedule> { 
     new Schedule { mintime = "01.01.2012", maxtime = "05.01.2012", weekday = "1" }, 
     new Schedule { mintime = "01.02.2012", maxtime = "10.02.2012", weekday = "2" }, 
     new Schedule { mintime = "01.03.2012", maxtime = "10.03.2012", weekday = "3" }, 
     new Schedule { mintime = "01.04.2012", maxtime = "10.04.2012", weekday = "4" } 
    }, 
    new List<Schedule> { 
     new Schedule { mintime = "05.01.2012", maxtime = "10.01.2012", weekday = "1" }, 
     new Schedule { mintime = "10.01.2012", maxtime = "20.01.2012", weekday = "2" }, 
     new Schedule { mintime = "01.03.2012", maxtime = "10.03.2012", weekday = "3" }, 
     new Schedule { mintime = "01.04.2012", maxtime = "10.04.2012", weekday = "4" } 
    }, 
    new List<Schedule> { 
     new Schedule { mintime = "05.01.2012", maxtime = "10.01.2012", weekday = "1" }, 
     new Schedule { mintime = "01.02.2012", maxtime = "10.02.2012", weekday = "2" }, 
     new Schedule { mintime = "01.03.2012", maxtime = "10.03.2012", weekday = "3" }, 
     new Schedule { mintime = "01.04.2012", maxtime = "10.04.2012", weekday = "4" } 
    }, 
};

？

是否有可能使用LINQ獲取它？

我的問題的主要議題是建立時間表清單。每個時間表應包括星期一，星期二，星期三，星期四，星期五，星期六和星期日一次。我需要使用一個更常見的列表來構建這樣的列表，其中包含許多針對星期一，星期三等的時間表。

來源

2012-09-25 kseen

你能不能精確你的問題？非常不清楚。 – Cybermaxs

你爲什麼用字符串表示日期？這會讓你很難幫助你。 –

@Cybermaxs對不起，我的英語。試圖改善問題。請參閱問題更新。 – kseen

使用Eric Lippert的CartesianProduct here

List<List<Schedule>> newList = CartesianProduct(list.GroupBy(l => l.weekday)) 
           .Select(x => x.ToList()) 
           .ToList();

來源

2012-09-25 11:48:26

非常酷。順便說一句，如果它是擴展方法，正確的順序應該是：'list.GroupBy（l => l.weekday）.CartesianProduct（）。選擇（x => x.ToList（））。ToList（）;'由於鏈接有時會變壞，你可以在這篇文章中包含該方法的代碼嗎？ –

@BradRem我知道但不是將代碼移動到一個靜態類，我只是刪除'this'來測試我的環境。 –

獲取所有的獨特變化

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