在PHP中傳遞變量Zend Framework

Question

我認爲我剛剛工作太久而且很累。我有一個使用Zend Framework的應用程序，其中顯示數據庫中的俱樂部列表。然後，我希望用戶能夠點擊該俱樂部並獲得俱樂部的身份標識，並將其發佈到另一個頁面以顯示更多信息。

這裏的俱樂部控制器：

class ClubsController extends Zend_Controller_Action 
{ 

    public function init() 
    { 

    } 

    public function indexAction() 
    { 
     $this->view->assign('title', 'Clubs'); 
     $this->view->headTitle($this->view->title, 'PREPEND'); 
     $clubs = new Application_Model_DbTable_Clubs(); 
     $this->view->clubs = $clubs->fetchAll(); 
    } 
} 

模型：

class Application_Model_DbTable_Clubs extends Zend_Db_Table_Abstract 
{ 

    protected $_name = 'clubs'; 

    public function getClub($id) { 
     $id = (int) $id; 
     $row = $this->fetchRow('id = ' . $id); 
     if (!$row) { 
      throw new Exception("Count not find row $id"); 
     } 
     return $row->toArray(); 
    } 
} 

的觀點：

<table> 
    <?php foreach($this->clubs as $clubs) : ?> 
    <tr> 
     <td><a href=''><?php echo $this->escape($clubs->club_name);?></a></td> 
     <td><?php echo $this->escape($clubs->rating);?></td> 
    </tr> 
    <?php endforeach; ?> 
</table> 

我想我剛開如何它使用Zend做困惑框架..

Answer 1

一個例子：

class ClubsController extends Zend_Controller_Action 
{ 

    public function init() 
    { 

    } 

    public function indexAction() 
    { 
     $this->view->assign('title', 'Clubs'); 
     $this->view->headTitle($this->view->title, 'PREPEND'); 
     $clubs = new Application_Model_DbTable_Clubs(); 
     $this->view->clubs = $clubs->fetchAll(); 
    } 

    public function displayAction() 
    { 
     //get id param from index.phtml (view) 
     $id = $this->getRequest()->getParam('id'); 
     //get model and query by $id 
     $clubs = new Application_Model_DbTable_Clubs(); 
     $club = $clubs->getClub($id); 
     //assign data from model to view [EDIT](display.phtml) 
     $this->view->club = $club; 
     //[EDIT]for debugging and to check what is being returned, will output formatted text to display.phtml 
     Zend_debug::dump($club, 'Club Data'); 

    } 
} 

[編輯] display.phtml

<!-- This is where the variable passed in your action shows up, $this->view->club = $club in your action equates directly to $this->club in your display.phtml --> 
<?php echo $this->club->dataColumn ?> 

認爲index.phtml

<table> 
    <?php foreach($this->clubs as $clubs) : ?> 
    <tr> 
    <!-- need to pass a full url /controller/action/param/, escape() removed for clarity --> 
    <!-- this method of passing a url is easy to understand --> 
     <td><a href='/index/display/id/<?php echo $clubs->id; ?>'><?php echo $clubs->club_name;?></a></td> 
     <td><?php echo $clubs->rating;?></td> 
    </tr> 
<?php endforeach; ?> 

的示例視圖使用url（）輔助

<table> 
     <?php foreach($this->clubs as $clubs) : ?> 
     <tr> 
     <!-- need to pass a full url /controller/action/param/, escape() removed for clarity --> 
     <!-- The url helper is more correct and less likely to break as the application changes --> 
      <td><a href='<?php echo $this->url(array(
       'controller' => 'index', 
       'action' => 'display', 
       'id' => $clubs->id 
      )); ?>'><?php echo $clubs->club_name;?></a></td> 
      <td><?php echo $clubs->rating;?></td> 
     </tr> 
    <?php endforeach; ?> 
</table> 

[編輯] 隨着你的模型當前的getClub（）方法建立您可能需要使用$club['data']訪問數據的方式。這可以通過從返回的值中刪除->toArray()來糾正。
如果您還沒有這樣做，您可以通過將以下行添加到.htaccess文件SetEnv APPLICATION_ENV development來激活屏幕上的錯誤消息。 使用你提供的信息，確保display.phtml住在application\views\scripts\club-description\display.phtml（我很確定這是正確的，ZF處理一些有趣的方式駱駝案件名稱）

Answer 2

你可以把俱樂部ID到您鏈接到可以在視圖中的href網址 - 比如/controllername/club/12，然後獲取這些信息與控制：

$clubId = (int) $this->_getParam('club', false); 

的「假」，將是一個默認值，如果沒有給出參數。 （int）是確保獲得數字的好習慣（如果是其他非數字字符串，則爲0）。

在你看來

Answer 3

做到這一點

<?php foreach ($this->clubs as $clubs) : ?> 
... 
<a href="<?php echo $this->url(array(
        'controller' => 'club-description', 
        'action' => 'index', 
        'club_id' => $clubs->id 
        ));?>"> 
... 

這樣，你必須在你的ClubDescription控制器的index動作可用club_id PARAM。你得到像這樣$this->getRequest()->getParam('club_id')