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我的程序計算每個學生的平均分數。它輸出數字平均值和字母等級。有了這兩個功能,我就可以得到每個學生的字母等級,,但我不知道如何獲得每個字母等級的總金額。 (請注意,我不能使用結構或數組或矢量等爲這項任務:()發出函數返回值
#include <iostream>
string letterScore(double&);
int scoreCounter(string&);
using namespace std;
int main() {
/* repeat for 5 students */
for (int i = 0; i < 5; i++) {
/* for simplicity, assume avgScore has already been calculated
and that function returned the average scores received for
each student: 90, 80, 70, 60, and 50 respectively */
// pass the average score to figure out letter grades
string letterscore = letterScore(avgScore);
}
return 0;
}
string letterScore(double& avgScore) {
int As, Bs, Cs, Ds, Fs = 0;
string letterscore;
if (avgScore >= 90)
{
letterscore = "A";
As = scoreCounter(letterscore);
}
else if (avgScore >= 80 && avgScore <= 89)
{
letterscore = "B";
Bs = scoreCounter(letterscore);
}
else if (avgScore >= 70 && avgScore <= 79)
{
letterscore = "C";
Cs = scoreCounter(letterscore);
}
else if (avgScore >= 60 && avgScore <= 69)
{
letterscore = "D";
Ds = scoreCounter(letterscore);
}
else if (avgScore >= 50 && avgScore <= 59)
{
letterscore = "F";
Fs = scoreCounter(letterscore);
}
return letterscore;
}
int scoreCounter(string& letterscore) {
int counter = 0;
if (letterscore == "A")
{
counter++;
}
else if (letterscore == "B")
{
counter++;
}
else if (letterscore == "C")
{
counter++;
}
else if (letterscore == "D")
{
counter++;
}
else if (letterscore == "F")
{
counter++;
}
return counter;
}
我知道問題出在第二個功能,我是如何連接兩個。現在,As,Bs,Cs,Ds,Fs的輸出是0而不是1(假設上面提到的90,80,70,60和50的平均值)。我怎樣才能回到main()
每個字母等級總數?謝謝!
謝謝你這一點,你釘它,它是那麼簡單。 – Blueshift