如何用PHP正確解析這段文字？我中途有

Question

我有詳細介紹有關包含單詞「紅粉」帶信息文本的該塊（從Discogs API）......

http://pastebin.com/3vBnC0aE

我試圖找出如何從這個文本塊中正確地提取藝術家名字。我的嘗試是：

<?php 
    $url = "https://api.discogs.com/database/search?type=artist&q=pink"; // add the resource info to the url. Ex. releases/1 

    //initialize the session 
    $ch = curl_init(); 

    //Set the User-Agent Identifier 
    curl_setopt($ch, CURLOPT_USERAGENT, 'YourSite/0.1 +http://your-site-here.com'); 

    //Set the URL of the page or file to download. 
    curl_setopt($ch, CURLOPT_URL, $url); 

    //Ask cURL to return the contents in a variable instead of simply echoing them 
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); 

    //Execute the curl session 
    $output = curl_exec($ch); 

    //close the session 
    curl_close ($ch); 



    function textParser($text, $css_block_name){ 

     $end_pattern = '], "'; 

     switch($css_block_name){ 
      # Add your pattern here to grab any specific block of text 
      case 'title'; 
       $end_pattern = '", "'; 
       break; 
     } 

     # Name of the block to find 
     $needle = "\"{$css_block_name}\":"; 

     # Find start position to grab text 
     $start_position = stripos($text, $needle) + strlen($needle); 

     $text_portion = substr($text, $start_position, stripos($text, $end_pattern, $start_position) - $start_position + 1); 
     $text_portion = str_ireplace("[", "", $text_portion); 
     $text_portion = str_ireplace("]", "", $text_portion); 

     return $text_portion; 
    } 

    $blockTitle = textParser($output, 'title'); 
    echo $blockTitle. '<br/>'; 



?> 

但是這給這個錯誤：

Warning: stripos(): Offset not contained in string in C:\xampp\htdocs\WellItsFixed3\TTpage1.php on line 41

41號線是

$text_portion = substr($text, $start_position, stripos($text, $end_pattern, $start_position) - $start_position + 1); 

的最終目標是能夠呈現所提取的帶標題的列表。

任何洞察讚賞。謝謝。

Answer 1

這顯然是一個JSON編碼字符串，你是用你的方法超調。只要做到：

$data = json_decode($your_string); 

和$data將包含結構化的方式，所有的信息，請參閱the json_decode() manual瞭解更多詳情。