laravel中的內部查詢5.3查詢構建器

Question

我試圖使用Laravel內部查詢來獲取數據，但我面臨一個問題，我將value變量作爲值傳遞給我的查詢，如下所示。

$seller_name = $request->seller_name; 
    $supplier_address = DB::table('supplier_addresses') 
     ->where('company_main_name', function($query) 
     { 
      $query->select('company_main_name') 
       ->where('company_name',$seller_name) 
       ->from('supplier_addresses') 
       ->get(); 
     }) 
     ->get(); 

如果我通過靜態值，而不是$seller_name那麼完美的作品，我查$seller_name不爲空，就說明沒有定義錯誤變量。

Answer 1

試試這個，你有use這樣的功能後，通過您的變量$

$seller_name = $request->seller_name; 
$supplier_address = DB::table('supplier_addresses') 
     ->where('company_main_name', function($query) use($seller_name) 
     { 
      $query->select('company_main_name') 
       ->where('company_name',$seller_name) 
       ->from('supplier_addresses') 
       ->get(); 
     }) 
     ->get(); 

Answer 2

你必須使用use像

$seller_name = $request->seller_name; 
$supplier_address = DB::table('supplier_addresses') 
    ->where('company_main_name', function($query) use ($seller_name) 
    { 
     $query->select('company_main_name') 
      ->where('company_name',$seller_name) 
      ->from('supplier_addresses')->get(); 
    }) 
    ->get(); 

Answer 3

你要通過變量匿名函數與use ($seller_name)

$seller_name = $request->seller_name; 
$supplier_address = DB::table('supplier_addresses') 
    ->where('company_main_name', function($query) use ($seller_name) 
    { 
     $query->select('company_main_name') 
      ->where('company_name',$seller_name) 
      ->from('supplier_addresses') 
      ->get(); 
    }) 
    ->get(); 

Answer 4

$seller_name = $request->seller_name; 
$supplier_address = DB::table('supplier_addresses') 
     ->where('company_main_name', function($query) use($seller_name) 
     { 
      $query->select('company_main_name') 
       ->where('company_name',$seller_name) 
       ->from('supplier_addresses') 
       ->get(); 
     }) 
     ->get(); 

你忘了使用use

Answer 5

你需要傳遞$seller_name使用use關閉。請不要在關閉查詢中使用get()以通過單個數據庫查詢來獲得結果。

$supplier_address = DB::table('supplier_addresses') 
    ->where('company_main_name', function($query) use ($seller_name) { 
     $query->select('company_main_name') 
      ->where('company_name', $seller_name) 
      ->from('supplier_addresses'); 
    }) 
    ->get(); 

此外，您的代碼與此相同。

$supplier_address = DB::table('supplier_addresses') 
    ->where('company_name', $seller_name) 
    ->get(); 

Answer 6

你要通過在功能使用變量（$ SELLER_NAME）

$seller_name = $request->seller_name; 
$supplier_address = 
    DB::table('supplier_addresses') 
     ->where('company_main_name', function($query) use ($seller_name) 
     { 
       $query->select('company_main_name') 
        ->where('company_name',$seller_name) 
        ->from('supplier_addresses') ->get(); 
     }) 
    ->get(); 

你可以在這裏參考文檔： https://laravel.com/docs/5.4/queries#conditional-clauses