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我正在MySQL數據庫上運行查詢,我正在使用JDBC並且正在使用MySQL工作臺來運行查詢。當我在MySQL工作臺中運行我的查詢時出現JDBC錯誤但沒有錯誤
當我在MySQL工作臺上運行它時,我得到了我期待的,但是當我在我的代碼中運行它時,我得到了它。
com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException:您的SQL語法錯誤;檢查對應於你的MySQL服務器版本在1號線
這裏附近使用「選擇Character.CharacterID,Character.CharacterName,Characte」正確的語法手冊在Java:
for (int i = 0; i < 3; i++) {
try {
result = s.executeQuery("USE `arbitrary-hero`; SELECT `Character`.CharacterID, `Character`.CharacterName, `Character`.CharacterLevel, SUM(ItemAttack), SUM(ItemHealth), SUM(ItemAgility), "
+ "SUM(ItemStrength), SUM(ItemSource) FROM `arbitrary-hero`.`Character` INNER JOIN `arbitrary-hero`.Character_Items ON `Character`.CharacterID = Character_Items.CharacterID INNER JOIN "
+ "Items ON Character_Items.ItemID = Items.ItemID WHERE Character_Items.Equiped = 1 and `Character`.CharacterName = "+ name[i] +" GROUP BY `Character`.CharacterName;;");
}
catch(Exception e) {
System.out.println(e);
}
}
s.close();
這裏是SQL:
SELECT `Character`.CharacterID, `Character`.CharacterName, `Character`.CharacterLevel, SUM(ItemAttack), SUM(ItemHealth), SUM(ItemAgility), SUM(ItemStrength),
SUM(ItemSource) FROM `arbitrary-hero`.`Character` INNER JOIN `arbitrary-hero`.Character_Items ON
`Character`.CharacterID = Character_Items.CharacterID INNER JOIN Items ON
Character_Items.ItemID= Items.ItemID WHERE Character_Items.Equiped = 1 and `Character`.CharacterName = "Maxinfet" GROUP BY `Character`.CharacterName;
Dor說得對。每個'executeQuery'方法調用一個SQL語句,請。順便說一下,您應該通過連接字符串來選擇mySQL數據庫(在USE語句中提到的數據庫)。 –
謝謝,只有一條SQL語句解決了這個問題。 –