-1
我想從這個查詢中得到結果,但我在使用group_concat和max case時遇到了問題。如何在MAX中使用GROUP_CONCAT(CASE WHEN ...)?
SELECT
t1.id,
t1.name,
MAX(CASE WHEN t2.code = t1.f_name THEN t2.name END) AS name2,
MAX(CASE WHEN t2.code = t1.l_name THEN t2.name END) AS name3,
MAX(CASE WHEN t2.code = t1.a_name THEN t2.name END) AS name4,
GROUP_CONCAT(MAX(CASE WHEN FIND_IN_SET(t3.code,t1.vehicles) THEN t3.name END) AS car_owned)
GROUP_CONCAT(MAX(CASE WHEN FIND_IN_SET(t3.code,t1.homes) THEN t3.name END) AS home_owned)
FROM
first_table AS t1 LEFT JOIN second_table AS t2
ON t2.code IN (t1.f_name, t1.l_name, t1.a_name)
LEFT JOIN second_table AS t3 ON FIND_IN_SET(t3.code,t1.vehicles) > 0 OR FIND_IN_SET(t3.code,t1.homes) > 0
GROUP BY
t1.id,
t1.name
任何幫助謝謝。小提琴是here
不知道我在下面。你能分享一些樣本數據和你試圖得到的結果嗎? – Mureinik 2014-11-24 07:38:53
我不知道你在做什麼 – Strawberry 2014-11-24 07:39:08
@Strawberry我在first_table列的home中選擇連接列時出現問題,而車輛已經連接了來自第二個表的連接值,現在我想從second_table獲取相關名稱。 – jones 2014-11-24 08:22:57