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休眠預測我有一個包含從該表下列字段爲彈簧引導應用
|id|feedback_status|financial_year|attendence|behaviour|total_feedback|user_id|total_behaviour|
蔭取feedback_status和total_feedback的表,並返回作爲使用JSON數據有突起和projectionlist冬眠。
List<StudentFeedback> results = null;
Session session = getSession();
Criteria criteria = session.createCriteria(StudentFeedback.class);
ProjectionList projlist = Projections.projectionList();
projlist.add(Projections.property("totalFeedback").as("qty"));
projlist.add(Projections.groupProperty("feedbackStatus").as("feedName"));
criteria.setProjection(projlist);
criteria.setResultTransformer(Transformers.ALIAS_TO_ENTITY_MAP);
results = criteria.list();
}
return GsonUtils.toGson(results);
}
我feedback_status和total_feedback包含下列值
|feedback_status| |total_feedback |
Excellent 23
Average 11
Poor 12
Good 13
Poor 12
所以,問題是無論何時返回JSON,它打印feedback_status
值poor
兩次,我想一次印刷只值並且如果它發生多於一次,則總結對應於feedback_status
的total_feedback
並返回到單個。
你好兄弟得到了答案, 你可以嘗試使用.setProjection(Projections.countDistinct( 「feedback_status」) ); 例如:標準條件= createCriteria(values).setProjection(Projections.countDistinct(「feedback_status」)); – Pradeep
@PradeepCG對於打印出來的結果很有幫助,因爲total_feedback? – BeginnerBro
嘿,你需要使用總和與計數限制,請檢查這些鏈接 http://stackoverflow.com/questions/23044565/count-with-other-fields-in-group-by-with-hibernate http: //stackoverflow.com/questions/23044565/count-with-other-fields-in-group-by-with-hibernate – Pradeep